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joja [24]
4 years ago
12

A string with one 10-g washer on the end is attached to the rearview mirror of a car. when the car leaves an intersection, the s

tring makes an angle of 6 ∘ with the vertical.
Physics
1 answer:
zhenek [66]4 years ago
7 0

Answer:

The acceleration of the car is 1.02 m/s².

Explanation:

Given that,

mass = 10 g

Angle = 6°

Suppose we need to find the acceleration of the car.

We need to calculate the tension

Using balance vertical force

T\cos\theta= mg

Put the value into the formula

T\cos6=0.01\times9.8

T=\dfrac{0.01\times9.8}{\cos6}

T=0.098\ N

We need to calculate the acceleration of the car

Using balance equation

T\sin\theta=ma

a=\dfrac{T\sin\theta}{m}

Put the value into the formula

a=\dfrac{0.098\times\sin6}{0.01}

a=1.02\ m/s^2

Hence, The acceleration of the car is 1.02 m/s².

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When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot
Softa [21]

Answer:

1.08 * 10^{14} J

Explanation:

Energy and mass are related by the famous equation developed by Albert Einstein:

E = mc^2

where m = mass and c = speed of light

This equation explains that an object with very small mass can produce a large amount of energy in reactions such as a nuclear reaction.

Hence, the energy produced by the explosion of a Plutonium bomb containing 3.6 grams of matter is:

E = 3.6 * 10^{-3} * (3 * 10^8)^2

E = 1.08 * 10^{14} J

3 0
3 years ago
Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho
Evgesh-ka [11]

Answer: t = 0.492τ

Explanation: In a circuit where there is a resistor and a capacitor, the equation for a charging capacitor is given by:

q = q_0(1 - e^{\frac{t}{RC} })

where:

q_0 is the equilibrium charge

q is the charge at time t

RC is time constant also called τ (tau)

For this problem, the circuit is charged to 39%, which means: q = 0.39 q_0

0.39q_0 = q_0 (1 - e^\frac{-t}{RC} )

0.39 = 1 - e^\frac{-t}{RC}

e^\frac{-t}{RC} = 0.61

\frac{-t}{RC} = ln(0.61)

-t = ln(0.61)τ

t = 0.492τ

For the condition to be met it is needed 0.492 time constants must elapse.

7 0
3 years ago
What was the voltage on the battery for the #2 series circuit with two light bulbs?A: 4 VB: 18 VC: 4.5 VD: 9 V
Ghella [55]

We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

R_t=R_1+R_2

That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:

V=IR

Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:

V=I(R_1+R_2)

8 0
1 year ago
A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec
Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

Tension in the string T = 60 N

Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 8=50.24rad/sec

Velocity of the string wave is equal to v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec

Power of wave propagation is equal to P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt

So power of the wave will be equal to 5.464 watt

6 0
3 years ago
A student performs an activity to study how electric current flows in a circuit. The student constructs two different circuits,
natta225 [31]

Native_Americans_in_the_United_State0000000000000000000000000

Explanation:

8 0
3 years ago
Read 2 more answers
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