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3 years ago

Which spacecraft appears the longest to an outside observer? W X Y Z

Physics

2 answers:

Ivenika [448]3 years ago

7 0

Answer:

Explanation:

pychu [463]3 years ago

3 0

Answer:

The correct answer is Y

I did on quiz and got it

Explanation:

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In scientific notation, (6.2 x 10^4) x (3.3 x 10^2 ) equals ____________________.

castortr0y [4]

You will get 20460000 as your answer which is broken down into, 2.046 x 10^7 as your number has to be between 1-10.

5 0

3 years ago

Read 2 more answers

Standard twist-on wire connectors are not suitable for terminating or splicing aluminum or copper-clad aluminum conductors.

Rainbow [258]

Answer:

True.

Explanation:

Twist-on wire connectors are a sort of electrical conduit used only to fasten two or more small tension (or extra-low tension) electrical conductors.They are also called wire nuts, wire connectors or cone connectors( because of their conical shape). They are not suitable for for terminating or splicing aluminum or copper-clad aluminum conductors.

Hence the above statement is true.

4 0

3 years ago

What is the weight in pounds of a 7.0 kilogram bowling ball on earth's surface

hodyreva [135]

Gravitational field strength (GFS) on earth =10 N/kg

Weight = GFS x mass
W = 10 x 7
W = 70N
70N = 15.74 pounds

3 0

3 years ago

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A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It

natta225 [31]

Answer:

P-value of the test statistic is 2.499

Explanation:

given data:

size sample is 24

sample mean is 414 gm

standard deviation is 15

Null hypotheis is

$H_0: \mu = 420 gm$

$H_1 \mu< 420$

level of significance is 0.01

from test statics

$t = \frac{\hat x - \mu}{\frac{s}{\sqrt{n}}}$

degree od freedom is = n -1

df = 24 -1 = 13

$t = \frac{414 - 420}{\frac{15}{\sqrt{24}}}$

t = -1.959

from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499

8 0

3 years ago

For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par

Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

initial temperature of metals, = $T_m$
initial temperature of water, = $T_i$
specific heat capacity of copper, $C_p$ = 0.385 J/g.K
specific heat capacity of aluminum, $C_A$ = 0.9 J/g.K
both metals have equal mass = m

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

For copper metal, the quantity of heat transferred is calculated as;

$Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t$

The change in heat energy for copper metal;

$\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t$

For aluminum metal, the quantity of heat transferred is calculated as;

$Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t$

The change in heat energy for aluminum metal ;

$\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t$

Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

Learn more here:brainly.com/question/15345295

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3 years ago