The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL
<h3>Balanced equation </h3>
2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 2
- The mole ratio of the base, Ca(OH)₂ (nB) = 1
<h3>How to determine the volume of Ca(OH)₂ </h3>
- Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
- Volume of acid, HCl (Va) = 36 mL
- Molarity of acid, HCl (Ma) = 1.63 M
- Volume of base, Ca(OH)₂ (Vb) =?
MaVa / MbVb = nA / nB
(1.63 × 36) / (1.48 × Vb) = 2
58.68 / (1.48 × Vb) = 2
Cross multiply
2 × 1.48 × Vb = 58.68
2.96 × Vb = 58.68
Divide both side by 2.96
Vb = 58.68 / 2.96
Vb = 19.8 mL
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The percent composition of the compound is 79.87 % of carbon and 20.12% of hydrogen
Explanation:
Given:
mass of carbon = 13.18 grams
mass of hydrogen = 3.32 grams
percent composition of compound =?
From the given data total mass of the compound is calculated
13.8 + 3.32
= 16.5 grams
The individual percentage of hydrogen and carbon will be calculated as:
percent composition = 
x 100
For carbon,
x 100
percent composition of carbon = 79.87 % of carbon.
for hydrogen:
= 20.12 % of hydrogen
In the compound given 79.87 % of carbon and 20.12% of hydrogen is present.
