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Ierofanga [76]
3 years ago
10

Suppose you were dissolving a metal such as zinc with hydrochloric acid

Chemistry
1 answer:
Ivanshal [37]3 years ago
8 0
So are you asking h<span>ow would the particle size of the zinc affect the rate of its dissolution?
you must now that t</span><span>he bigger the particle the lesser the dissolution.
</span>The reaction rate will go as the total surface area, t<span>herefore, the smaller the particles the faster the reaction. </span>
<span>This relationship is NOT linear.</span>
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A welding tank of oxygen gas has a volume of 100. L. The oxygen in the tank is at a pressure of 95 atm and a temperature of 30.
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5 0
3 years ago
What should a simplified model of a large molecule like glucose show?
maxonik [38]

Glucose is the simplest sugar and carbohydrate that provides energy. The simplified model of glucose (C₆H₁₂O₆) shows carbon, hydrogen, and oxygen atoms linked together.

<h3>What is glucose?</h3>

Glucose is an example of a carbohydrate macromolecule that is further classified as a monosaccharide. They are crystalline and fundamental units of carbohydrates.

The molecular formula of glucose is C₆H₁₂O₆ and the mass is 180.156 g/mol. It is an aldohexose that contains an aldehydic functional group. In its structure, there are six oxygen atoms, six carbon atoms, and twelve hydrogen atoms.

Therefore, the glucose molecule is composed of C, H, and O.

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5 0
1 year ago
Where is the genetic code located again in the dna molecule again?
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The DNA is in the nucleus.

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The nucleus is the power house of the cell, the little sting things inside are the strands of DNA.

8 0
3 years ago
How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 163 mL of coffee at 97.9°C so that the r
Stolb23 [73]

Answer:

248 mL

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by water (Qw) and the heat released by the coffee (Qc) is zero.

Qw + Qc = 0

Qw = -Qc [1]

We can calculate each heat using the following expression.

Q = c × m × ΔT

where,

  • c: specific heat
  • m: mass
  • ΔT: change in the temperature

163 mL of coffee with a density of 0.997 g/mL have a mass of:

163 mL × 0.997 g/mL = 163 g

From [1]

Qw = -Qc

cw × mw × ΔTw = -cc × mc × ΔTc

mw × ΔTw = -mc × ΔTc

mw × (54.0°C-25.0°C) = -163 g × (54.0°C-97.9°C)

mw × 29.0°C = 163 g × 43.9°C

mw = 247 g

The volume corresponding to 247 g of water is:

247 g × (1 mL/0.997 g) = 248 mL

8 0
3 years ago
A sample of gas has a volume of 75.0 mL at 30.0 psi. Determine the pressure of the gas if its volume is changed to 15 mL and its
Assoli18 [71]

Answer:

5.995 psi

Explanation:

30 psi = 2.04 atm

75 mL = 0.075 L

15 mL = 0.015 L

0.075 L/ 2.04 atm = 0.015 L/x

0.075x = 0.0306

x = 0.408

0.408 atm = 5.995 psi

4 0
3 years ago
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