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Grace [21]
4 years ago
14

Please help asap, thank you!

Chemistry
1 answer:
yKpoI14uk [10]4 years ago
6 0
The answer is coastal upwelling.
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Please answer ................
nataly862011 [7]

Answer:

Explanation:

i. SO2

ii. Na2O

3 0
2 years ago
Describe how you could use two LB/agar plates, some E. coli, and some ampicillin to determine how E. coli cells are affected by
KiRa [710]

Answer:

For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin.  Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.

Explanation:

If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.

8 0
3 years ago
A chemist requires 5.00 liters of 0.420 M H2SO4 solution. How many grams of H2SO4 should the chemist dissolve in water? 129 gram
natali 33 [55]

Answer:

Approximately 206 grams.

Explanation:

How many moles of sulfuric acid \mathrm{H_2SO_4} are there in this solution?

\text{Number of moles of solute} = \text{Concentration} \times \text{Volume}.

The unit for concentration "\mathrm{M}" is equivalent to mole per liter. In other words, \rm 1\;M = 1\; mol\cdot L^{-1}. For this solution, the concentration of \mathrm{H_2SO_4} is \rm 0.420\;M = 0.420\; mol\cdot L^{-1}.

\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V\\&= \rm 0.420\;mol\cdot L^{-1}\times 5.00\; L \\&= \rm 2.10\; mol\end{aligned}.

What's the mass of that \rm 2.10\; mol of \mathrm{H_2SO_4}?

Start by finding the molar mass M of \mathrm{H_2SO_4}.

Relative atomic mass data from a modern periodic table:

  • H: 1.008;
  • S: 32.06;
  • O: 15.999.

\displaystyle M(\mathrm{H_2SO_4}) = 2\times \underbrace{1.008}_{\mathrm{H}} + 1\times \underbrace{32.06}_{\mathrm{S}} + 4\times \underbrace{15.999}_{\mathrm{O}} = \rm 98.072\;g\cdot mol^{-1}.

\text{Mass} = \text{Quantity in moles} \times \text{Molar Mass}.

m = n \cdot M = \rm 2.10\; mol \times 98.072\;g\cdot mol^{-1} \approx 206\; g.

In other words, the chemist shall need approximately 206 grams of \mathrm{H_2SO_4} to make this solution. As a side note, keep in mind that the 206 grams of \mathrm{H_2SO_4} also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.

6 0
4 years ago
67g of K2O is how many moles
taurus [48]
Follow the formula.. there’s not enough in this question for me to solve
7 0
3 years ago
What is the combined gas law formula ?
Lera25 [3.4K]
P = pressure, V = volume, T = absolute temperature k = constant.
4 0
3 years ago
Read 2 more answers
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