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3 years ago

What do coefficients in chemical equations tell you?

Chemistry

1 answer:

Juliette [100K]3 years ago

5 0

More information ^^^

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What is the density of a sample of a substance with a volume of 120ml<br> and a mass of 90g?

tigry1 [53]

Answer:

<h3>The answer is 0.75 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 90 g

volume = 120 mL

We have

$density = \frac{90}{120} = \frac{9}{12} = \frac{3}{4} \\$

We have the final answer as

Hope this helps you

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3 years ago

What happens to traits when mutations happen

Wittaler [7]

Physical or mental traits change

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4 years ago

Identify the number of each type of atom in this formula 5C12H22O11<br><br>wdym

Lady bird [3.3K]

There are 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms in one molecule of C12H22O11.
In five molecules there are 60 carbon atoms, 110 hydrogen atoms, and 55 oxygen atoms.

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3 years ago

The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H

Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

$\Delta T_f=k_f\times m$

or,

$\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}$

where,

$\Delta T_f$ = change in freezing point

$k_f$ = freezing point constant (for benzene} = $5.12^0Ckg/mol$

m = molality

Putting in the values we get:

$0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}$

${\text{ Mass of solute in g}}=0.028g$

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

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3 years ago

What does it mean for energy to be conserved

marysya [2.9K]

Answer: It means that the energy is being stored or preserved to be used at a later time.

Your question was a little vague, so if this isn't the answer you were looking for, just let me know and I'll fix it.

Hope this helps! Good luck! :D

6 0

3 years ago