IMA = Ideal Mechanical Advantage
First class lever = > F1 * x2 = F2 * x1
Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2
=> F1/F2 = x1 /x2
IMA = F1/F2 = x1/x2
Now you can see the effects of changing F1, F2, x1 and x2.
If you decrease the lengt X1 between the applied effort (F1) and the pivot, IMA decreases.
If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.
If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.
If you decrease the applied effort (F1) and decrease the distance between it and the pivot (X1) IMA will decrease.
Answer: Increase the length between the applied effort and the pivot.
Answer:
This is the answer
Explanation:
You can find the ans in the photo I attached.
--vertical from ground to top--
v^2 = u^2 + 2as
with v= 0, a=g, s=u^2/(-2g)
g on the moon is 1/6
u is equal, then it goes 6 times higher on the moon.
v = u + at
with v= 0, a=g, t = u/(-g)
g on the moon is 1/6
u is equal, then it takes 6 times longer on the moon.
--horizontal--
s = vt , v is equal
t on the moon is 6 time longer
it moves 6 times farer on the moon
Answer:
(c) 6.91x10^14 Hz
Explanation:
Find the level energy of n=2 and n=5, using the formula:
where 
To jump from n=2 to n=5 the electron absorbs a photon with energy equal to 
, using the next formula to find specific wavelength 
to that energy
Where 
is the speed of light (
) and 
is Planck's constant (
). Solve for :
The frequency of this wavelength is calculated with this formula:
