Answer:
Explanation:
First Question
This question has to do with the mass defect in AMU.
It would get closer to the actual answer if I knew what mass of proton you are using and the mass of one neutron as well.
<u>Formula</u>
- Am = Z*m_h + (A - Z)*m_n - M
- Am is the mass defect
- Z is the atomic number (number of protons). 29
- m_h is the accepted mass of a proton. 1.0078
- A = Atomic Mass number 63
- m_n = mass of the neutron 1.0087
- M is the actual mass of the atom in question. 62.92958
<u>Solution</u>
Am = 29*1.0078 + (63 - 29)*1.0087 - 62.92958
Am = 0.59242 u The difference between what I get and D is that I don't exactly know what m_h and m_n are.
Second Question
The first step is to calculate the mass defect. Just use the formula above.
<u>Givens</u>
- Am = ?
- Z = 7
- A = 14
- m_h = 1.0078
- m_n = 1.0087
- M = 14.00307
Solution
Am = 7*1.0078 + (14 - 7)*1.0087 - 14.00307
Am=0.11243 u
1 u = 931.5 MeV
0.11243 u = x
x = 104.7285
This is more of a reading problem than a physics problem. They want the energy per nucleon, which is 14 (neutrons and protons).
E = 104.7285/14
E = 7.5 MeV
Answer
A
Answer: <u>Option A: </u>The gas and food are examples of energy.
Explanation:
Work and energy are inter-related. Energy is required to do the work. An equal amount of energy is converted into work. Work and energy have same units. The SI unit is Joule.
The gas and food are sources of energy. They act as fuel. This energy is utilized to perform work. The gas is used to run the car. The food is metabolized inside the body which is a source of energy and utilized to perform every day work.
Hence, The gas and food are examples of energy.
Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | =
Answer:
The magnitude of vector u is 3√5.
Answer:
(1) fossel fuel
(2) Kyoto protocol
(3) all of the above
(4) Electricity usage will decrease in the near future due to shrinking world population
Answer:
Explanation:
So we want the speed to go from 25 m/s to 0 m/s in 170 m, but the time needs to incorporate the reaction time, so the slowing down will not start until .68 s pass. Or, in other words, the train will travel an extra 25 m/s * .68 s = 17 m. This means, instead of 170 m to slow down it has 153. Hopefully that makes sense. With this information we can use the equation vf^2-vi^2=2ad. If that equation is unfamiliar you need to get a better handle on your physics equations.
Anyway, let's plug in.
vf = 0 m/s
vi = 25 m/s
a is what we're trying to find
d = 153 m
vf^2-vi^2=2ad
a = (vf^2-vi^2)/(2d)
Can you handle figuring it out from there? or if there is something you don't understand let me know.