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Anuta_ua [19.1K]
2 years ago
9

This group of elements is in group 2?

Physics
1 answer:
asambeis [7]2 years ago
5 0

Answer:

If you meant the Periodic Table it's the alkaline-earth metal

beryllium (Be)

magnesium (Mg)

calcium (Ca)

strontium (Sr)

barium (Ba)

radium (Ra)

Explanation:

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Explain why machine can"t be <br>100% efficient practically?​
Zigmanuir [339]

Answer:

Heat

Explanation:

Heat is the main component in why everything is not 100% efficient. Heat is a byproduct of everything and cannot be avoided.

5 0
3 years ago
Read 2 more answers
A steel rod is pulled in tension with a stress that is less than the yield strength. The modulus of elasticity may be calculated
pshichka [43]

Answer:

B. Axial stress divided by axial strain

Explanation:

Elasticity:

It is the tendency of an object to deform along the axis when an opposing force is applied without facing permanent change in shape.

Plasticity:

When an object crosses the elasticity limit, it enters plasticity where the change due to stress is permanent and the object might even break.

Yield strength:

Yield strength is the point of maximum bearable stress that indicates the limit of elasticity.

Our case:

As the stress applied is less than the yield strength, the rod is still in the elasticity state and its modulus can be calculated.

Modulus of Elasticity = Stress along axis/Ratio of change in length to original length

Axial strain is basically the ratio of change in length to original length.

So, Modulus of Elasticity = Axial Stress/ Axial Strain

6 0
3 years ago
HI PLEASE HELP, I ONLY HAVE 10 MINUTES
Whitepunk [10]

Answer:

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Explanation:

5 0
3 years ago
What increases your ability to see at night
PtichkaEL [24]
The answer would be increased number <span />of rod cells.Hope this helps :)


8 0
3 years ago
A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?
iris [78.8K]

Answer:

\Delta x=22.67786838m

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2 (1)

Where:

y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis

y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis

v_o=initial\hspace{3}velocity

t=travel\hspace{3}time

g=gravity\hspace{3}constant

\theta=Initial\hspace{3}launch\hspace{3}angle

In this case:

\theta=0

Because the dog jumps horizontally

Let's asume the gravity constant as:

g=9.8

y=0

Because when the dog reach the base the height is 0

y_o=70

v_o=6

Now let's replace the data in (1)

y_o-\frac{1}{2} *(9.8)*t^2+70

Isolating t:

t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473

Finally let's find the horizontal displacement using this equation:

\Delta x=v_o*cos(\theta)*t

Replacing the data:

\Delta x=6*1*3.77964473=22.67786838m

8 0
3 years ago
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