Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl
<u>Explanation:</u>
In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,
Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl
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Which of those depend on mayfly nymphs. In other terms which animal eats mayfly nymphs?
I would say frogs
Answer:
2H⁺ + NO₃⁻ + 1e⁻ → NO₂ + H₂O
Explanation:
NO₃⁻ → NO₂
In left side, Nitrogen acts with +5 by oxidation number
In right side, the oxidation number is +4
This is a reduction reaction, because the oxidation number has decreased. So the N has gained electrons.
NO₃⁻ + 1e⁻ → NO₂
In acidic medium, we have to add water, where there are less oxygens to ballance the amount. We have 2 O in left side, and 3 O in right side, so we have to add 1 H₂O on left side.
NO₃⁻ + 1e⁻ → NO₂ + H₂O
Now that oxygens are ballanced, we have to ballance the hydrogens by adding protons in the opposite side
2H⁺ + NO₃⁻ + 1e⁻ → NO₂ + H₂O
Answer:
Sulfur dioxide is a covalent bond because we have two non-metals (Sulfur and Oxygen).
(<em>Sulfur dioxide formula)</em>
It's called Sulfur dioxide but it can be called Sulfurous anhydride and Sulfur (lV) oxide.
Sulfur dioxide can have different reactions:
-
In the presence of oxygen oxidation of sulfur dioxide to sulfur trioxide occurs and the formula is:
The equal is because it's a reversible equation. This reaction is spontaneous.
- The sulfur trioxide reacting with water produces sulfuric acid. The formula is:
- Also the sulfur dioxide reacting with sodium hydroxide produces sodium sulfite and the formula is:
- And finally we have the reduction of sulfur dioxide (it can be in presence of hydrogen sulfide) getting elemental sulfur and water. The formula is:
