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2 years ago

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State two different structural isomers of 5 carbon hydrocarbon. hint cis and trans

1 answer:

scoundrel [369]2 years ago

4 0

I hope this helps, if you don't know I can explain

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Gallium is a solid metal at room temperature but melts at 29.9 °C. If you hold gallium in your hand, it melts from body heat. Ho

matrenka [14]

Answer: 4.56 Joules

Explanation:-

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed = ?

m= mass of substance = 2.5 g

c = specific heat capacity = $0.372J/g^0C$

Initial temperature = $T_i$ = 25.0°C

Final temperature = $T_f$ = 29.9°C

Change in temperature , $\Delta T=T_f-T_i=(29.9-25.0)^0C=4.90^0C$

Putting in the values, we get:

$Q=2.5\times 0.372\times 4.90^0C$

$Q=4.56J$

The heat absorbed by gallium must be 4.56 Joules

7 0

2 years ago

Egg white, marshmallow, and smoke from a smokestack are examples of _____. suspensions colloids solutions

d1i1m1o1n [39]

They are an example of colloids .....

6 0

2 years ago

What is the mass in grams of 8.65 mol C8H18?

aliina [53]

Answer:

m = 998 g

Explanation:

Hello there!

In this case, according to the definition of the molar mass as the mass of one mole of the compound, it is possible to state the 1 mole of C8H18 has a mass of 114.26 grams; therefore, the mass in 8.65 moles turn out to be:

$m=8.65mol*\frac{114.26g}{1mol}\\\\m=998g$

In agreement to the notation requirement.

Best regards!

5 0

2 years ago

What is a promblem based on charles' law?

LUCKY_DIMON [66]

Answer:

You will never know the exact volume with charles law

Explanation:

Doubling the temperature of gas doubles its volume, so long as the pressure and quantity of the gas are unchanged.

5 0

3 years ago

Read 2 more answers

Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma

Elena-2011 [213]

Answer:

The yearly release of $CO_2$ into the atmosphere is $6.73\times 10^{10} kg$ .

Explanation:

$CaCO_3(s)\rightarrow CaO(s) + CO_2(g)$

Annual production of CaO = $8.6\times 10^{10} kg=8.6\times 10^{13} g$

Moles of CaO :

$\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles$

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with $1.53\times 10^{12} moles$ of CaO moles of carbon-dioxide moles produced will be:

$\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles$ of carbon-dioxide

Mass of $1.53\times 10^{12}$ moles of carbon-dioxide:

$1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg$

The yearly release of $CO_2$ into the atmosphere is $6.73\times 10^{10} kg$ .

6 0

2 years ago