Answer:
A: 1.962
B: 3.924
Explanation:
g = G *M /R^2
g = 9.807*M/R^2 the gravitational constant of ground level on earth is about 9.807
g = 9.807*5lbs/R^2 the average brick is about 5 pounds.
g = 9.807*5*10^2. I'm assuming the height is around ten feet to help you out.
with these numbers plugged in you get an acceleration of 0.4905 a final velocity after 4 seconds 1.962. It's height fallen after 4 seconds is 3.924.
( M = whatever the brick weighs it's not specified in the question)
(R = the distance from the ground or how high the scaffold is)
(hopefully you can just plug your numbers in there hope this helps)
The rotational speed of the two children is the same.
In fact, it is defined as
![\omega = \frac{\Delta \theta}{\Delta t}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%20%5Cfrac%7B%5CDelta%20%5Ctheta%7D%7B%5CDelta%20t%7D%20)
where
![\Delta \theta](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta)
is the angle covered in the time
![\Delta t](https://tex.z-dn.net/?f=%5CDelta%20t)
. As it can be seen, this quantity does not depend on the distance from the centre, so the rotational speed is 4.0 revolutions per minute for both children.
1. Cenozoic ERA
2. Mesozoic ERA
3. Paleozoic ERA