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grandymaker [24]

2 years ago

9

The frequency of light emitted from hydrogen present in the Andromeda galaxy has been found to be 0.10% higher than that from hy

drogen measured on Earth.
Is this galaxy approaching or receding from the Earth, and at what speed?

1 answer:

Aloiza [94]2 years ago

4 0

Answer:

3x10^5m/s

Explanation:

See attached file

Explanation:

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A soil sample is 25 percent sand, 55 percent clay, and 20 percent silt. Use the following soil texture triangle to determine the

vova2212 [387]

I believe the answer is A. clay
The amount of clay alone determine which type of soil it would be according to the Triangle.
At that triangle, we could see that the maximum amount of clay to be considered as 'sandy clay' is 50.
Since the amount of sand surpassed that, it automatically fall into clay type even without having to look to other composition.

5 0

3 years ago

An object is moved 29 meters with a force of 289 N. what is the work done

Shtirlitz [24]

Answer:

8381

Explanation:

Workdone=Force x distance

W= 289x 29

W=8381J

8 0

2 years ago

In 1780, in what is now referred to as "Brady's Leap," Captain Sam Brady of the U.S. Continental Army escaped certain death from

zysi [14]

The minimum speed with which Captain Brady had to run off the edge of the cliff to make it safely to the far side of the river is around 6 meters per second.

<h3>Further explanation</h3>

This is a free fall 2-dimensional type of problem, therefor we can write equations for both dimensions which model the fall of captain Brady. Let's call <em>x </em>the distance travelled by the captain on the horizontal direction and <em>y </em>the distance travelled on the vertical direction.

Lets suppose that Brady jumped with a complete horizontal velocity from a point which we will call the origin (meaning zero horizontal and vertical displacement), and let's call <em>ta</em> the time it took for captain Brady to reach the river (meaning the time he spent on the air). The equations of motion for the captain will be:

$x= V \cdot t$

$y= - \frac{g \cdot t^2}{2}$

We know that at time <em>ta</em> the captain would have traveled 6.7 m on the horizontal direction, and 6.1 m in the vertical direction. Therefor we can write that:

$6.7= V \cdot ta$

$-6.1= - \frac{g \cdot {ta}^2}{2}$

Which gives us a system of 2 equations and 2 unknowns (<em>V</em> and <em>ta</em>). From the second equation we can solve for <em>ta</em> as:

$ta = \sqrt{\frac{2 \cdot 6.1}{g}} =1.12 s$

And solving for <em>V</em> on the first equation, we find that:

$V= \frac{6.7}{1.12} = 5.98 \frac{m}{s}$

Which is almost 6 meters per second.

<h3>Learn more</h3>

Free fall of an arrow: brainly.com/question/1597396
Concept of free fall: brainly.com/question/1708231

<h3>Keywords</h3>

Free fall, projectile, gravity

7 0

2 years ago

Read 2 more answers

What is the earths slant called

pochemuha

<span>it is called the axial tilt

</span>

5 0

2 years ago

A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of

alexandr402 [8]

Answer:

145.91 m

Explanation:

Data provided in the the question:

Wavelength of radio wave, $\lambda = \frac c f$

Here, c is speed of radio wave in air = 3 × 10⁸ m/s

f is the frequency = 514 kHz = 514 × 10³ Hz

Thus,

Wavelength = (3 × 10⁸) ÷ (514 × 10³) m

or

Wavelength = 583.65 m

Thus,

The height of the antenna will be

= $\frac \lambda 4$ = 583.65 ÷ 4 m

= 145.91 m

3 0

3 years ago