Answer:
Hydrated chromium(III) phosphate or chromium(III) phosphate tetrahydrate.
Answer:
67.5 moles of O2
Explanation:
2 C
8
H
18 + 27
O
2 → 16
C
O
2 + 18
H
2
O
According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...
170km/h this probs right i think
Answer:
75 g
Step-by-step explanation:
<em>Step 1</em>. Calculate the molar mass of CO₂
C = 12.01
2O = 2 × 16.00 = <u>32.00
</u>
Total = 44.01 g/mol
<em>Step 2</em>. Calculate the mass of CO₂
Mass of CO₂ = 6 mol CO₂ × (44.01 g CO₂/1 mol CO₂)
Mass of CO₂ = 75 g CO₂