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marusya05 [52]
3 years ago
6

An object with a mass of 15 kg has an acceleration of 3 m/s/s. What is the force

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:

45N

Explanation:

force=mass×acceleration

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Light elements with an atomic number less than 20 generally have a neutron to proton ratio equal to
Natalija [7]
Atomic elements consist of a nucleus that contains protons and neutrons. Protons carry a positive charge whilst neutrons are electrically neutral. In light elements with an atomic number less than 20, the neutron to proton ratio is generally equal to 1:1. This changes for heavier elements since the Coulomb interaction between many protons gets stronger and demands more neutrons for the nucleus to remain stable. 
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3 years ago
At a constant temperature, 600 mL of an ideal gas is at a pressure of 760 mmHg . If the volume is decreased to 300 mL, the press
belka [17]

Answer:

1520mmHg

Explanation:

Data obtained from the question include:

V1 (initial volume) = 600 mL

P1 (initial pressure) = 760 mmHg

V2 (final volume) = 300 mL

P2 (final pressure) =.?

Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:

P1V1 = P2V2

760 x 600 = P2 x 300

Divide both side by 300

P2 = (760 x 600) /300

P2 = 1520mmHg

The final pressure of the gas is 1520mmHg

7 0
3 years ago
Is zinc carbide a metallic bond?
Feliz [49]
Metallic bonds are found in metals like zinc.
3 0
3 years ago
Which of the following subatomic particles is uncharged?
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4 0
3 years ago
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In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0
sp2606 [1]

Answer:

The value of K_p for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = p^o_{H_2O}=15.0 Torr

Partial pressure of hydrogen gas at equilibrium = p^o_{H_2}=?

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

P=p^o_{H_2O}+p^o_{H_2}

p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr

3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)

The expression of K_p is given by:

K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}

K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066

The value of K_p for this reaction at 1200 K is 4.066.

6 0
3 years ago
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