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iVinArrow [24]
3 years ago
5

If the distance between two asteroids is halved, the gravitational force they exert on each other will

Physics
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_{1} & m_{2}) and the distance between them (r) in the next way:

F=G\frac{m_{1}m_{2}}{r^{2}} (2)

Now if distance between asteroids is halved:

F_{2}=G\frac{m_{1}m_{2}}{(\frac{r}{2})^{2}}

F_{2}=G\frac{m_{1}m_{2}}{\frac{r^{2}}{4}}

F_{2}=G\frac{4m_{1}m_{2}}{r^{2}}=4G\frac{m_{1}m_{2}}{r^{2}}

Note that G\frac{m_{1}m_{2}}{r^{2}} because (1) is F so:

F_{2}=4F

It's four times greater!

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The magnitude of the electric force on the charge is 5 N.

<h3>Magnitude of force on the charge</h3>

The magnitude of force on the charge is calculated as follows;

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