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ratelena [41]
3 years ago
13

1. How many liters of a 0.50 M solution are needed to give 3.5 moles of solute?

Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer:

The volume of solution in liters required to make a 0.250 M solution from 3.52 moles of solute is 14.08 liters of solution

Explanation:

The question relates to the definition of the concentration of a solution which is the number of moles per liter (1 liter = 1 dm³) of solution

Therefore we have;

The concentration of the intended solution = 0.250 M

Therefore, the number of moles per liter of the required resolution = 0.250 moles

Therefore, the concentration of the required solution = 0.250 moles/liter

The volume in liters of the required solution that will have 3.52 moles of the solute is given as follows;

The required volume of solution = The number of moles of the solute/(The concentration of the solution)

∴ The required volume of solution = 3.52 moles/(0.250 moles/liter) = 14.08 liters

The required volume of solution to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

Therefore the number of liters required to make a 0.250 M solution from 3.52 moles of solute = 14.08 liters.

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Nickel contains more atoms
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What type of mixture is separated by effusion and condensation?
icang [17]

Answer:

c is the answer then check it out

6 0
2 years ago
A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo
zheka24 [161]

Explanation:

The given data is as follows.

         Width of Styrofoam = 24.0 cm

          Length of Styrofoam = 36.0 cm

          Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

                  Volume = length × width × height

                                =  (36.0 × 24.0 × 5.0) cm^{3}

                                 = 4320 cm^{3}

or,                             = 4.32 \times 10^{3} cm^{3}

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

          24.0 cm × 36.0 cm × 2.0 cm

         = 1.73 \times 10^{3} cm^{3}

Hence, mass of displaced water is as follows.

                 mass = density × volume

                           = 1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}

                           = 1.73 \times 10^{3} g

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

             Mass of water displaced = mass of book + mass of Styrofoam

                  1.73 \times 10^{3} g = 1500 g + mass of Styrofoam

                   (1730 - 1500) g = mass of Styrofoam

                   mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

                   Density = \frac{mass}{volume}  

                                 = \frac{230}{4.32 \times 10^{3} cm^{3}}

                                 = 53.24 \times 10^{-3} g cm^{-3}

Thus, we can conclude that the density of Styrofoam is 53.24 \times 10^{-3} g cm^{-3}.

4 0
2 years ago
Pierce conducts an experiment in which waves collide in a way that the energy increases, which means that has occurred
Vikki [24]
<h2>Answer:</h2>

It means the waves collides and constructive interference occurred.

<h3>Explanation:</h3>

If the two waves coming from the opposite direction collide with each other, there are two way of their interference.

  • Constructive interference: An interference which results in the increase in energy. And it is when crust of a wave comes on the crust of second wave.
  • Destructive interference: An interference which results in decrease in energy of the resulting wave and colliding waves cancel the result of each other.

Hence in experiment there will be constructive interference.

8 0
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Answer: Boyle's law

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P_1V_1=P_2V_2

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