Answer:
It's simpler than most questions :)
Explanation:
1) B
2) B
3) D
4) A
5) A
Hope this will help :)
Explanation:
As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.
As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.
![NaCl \rightarrow Na^{+} + Cl^{-}](https://tex.z-dn.net/?f=NaCl%20%5Crightarrow%20Na%5E%7B%2B%7D%20%2B%20Cl%5E%7B-%7D)
So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.
Therefore, concentration of chlorine ions will be calculated as follows.
Concentration of
ions =
= 0.6 mM
Thus, we can conclude that the concentration of chloride ions is 0.6 mM.
The question here is solved using basic chemistry. CaCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of CaCl2 that dissolves.
CaCl2(s) --> Ca+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.65 mol CaCl2/1L × 2 mol Cl⁻ / 1 mol CaCl2 = 1.3 M
The answer to this question is [Cl⁻] = 1.3 M
The answer is 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
<h3>
What is Molarity ?</h3>
Molarity is defined as the amount of solute (in moles)in per litre of solution.
It is also known as molar concentration of a solution , It is expressed in mol/l
![\rm M =\dfrac{moles \;of\; solute}{Volume \;of \;solution} \\\\\\\rm M = \dfrac{n}{V} \\](https://tex.z-dn.net/?f=%5Crm%20M%20%3D%5Cdfrac%7Bmoles%20%5C%3Bof%5C%3B%20solute%7D%7BVolume%20%5C%3Bof%20%5C%3Bsolution%7D%20%5C%5C%5C%5C%5C%5C%5Crm%20M%20%3D%20%5Cdfrac%7Bn%7D%7BV%7D%20%5C%5C)
We can rearrange this equation to get the number of moles:
n= M * V
The molarity of solution is 8.3 M and the volume given is 4 litres
the moles will be n = 8.30 * 4 = 33.2 moles
Therefore 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
To know more about molarity
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