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2 years ago

Confused as heck. please help!

Chemistry

1 answer:

Nitella [24]2 years ago

6 0

Answer: that all thre water cycle and C is vaporation

Explanation:

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What structural feature of lecithin allows it to behave like an emulsifying agent?

stepladder [879]

Lecithin is an emulsifier agent that's composed of 5 smaller molecules: phosphoric acid, choline, glycerol( is the backbone), and two fatty acids.

The fatty acids, which are hydrophobic (afraid of water), makes this substance more similiar to fats and represent the non-polar part of the lecithin.
The phosphate group is the polar portion of the molecule and it's the negatively charged. The choline is positively charged, which readily dissolve in water.

Lecithin is a good emulsifier because of these structural features. the hydrophobic contacts with the oil, while the hydrophilic end contacts with the water.

6 0

3 years ago

A mass of 100.0 g of solute is dissolved in water so that 850. mL of a 0.7500 M solution has been prepared. What is the molar ma

zmey [24]

Answer:

156.86 g / mol

Explanation:

We start from the molarity law

Cm = n / V

n = w / M

then

Cm = (w / M) / V

Cm = w / (M × V)

where:

Cm is the molarity

n number of moles

w a mass of the solute

M is the molar mass of the solute (which is needed)

V the volume of the solution in liters

Then the M can be calculated as following:

M = w / (Cm × V)

M = 100 / (0.75 × 0.85) = 156.86 g / mol

8 0

4 years ago

28. Which of the following reactions at equilibrium would NOT be affected by volume

Svetradugi [14.3K]

Answer:

Explanation:

is the

6 0

3 years ago

Use the following MO diagram for Be2, Be2+, and Be2-. Based on this diagram,

Marta_Voda [28]

Bond Order = [Σ (bonding e-) - Σ (antibonding e-)]/2
Be2 = 4e = σ1(2e) σ2*(2e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0 
[Be2]+ = 3e = σ1(2e) σ2*(1e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0.5 
[Be2]+ would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order

6 0

3 years ago

Read 2 more answers

The pH of a 0.29 M solution of carbonic acid (H2CO3) is measured to be 3.44. Calculate the acid dissociation constant Ka of carb

arsen [322]

Answer: 4.55x10^-7

Explanation:

H2CO3 + H20 <==> H3O+ + HCO3-

Desigining an ICE table, we have:

Initial conc. of H2CO3 = 0.29 M

Initial conc. of H3O+ = 0

Initial conc. of HCO3- = 0

Change in conc. of H2CO3 = - x

Change in conc. of H3O+ = x

Change in conc. of HCO3- = x

Equilibrium conc. of H2CO3 = 0.29 - x

Equilibrium conc. of H3O+ = x

Equilibrium conc. of HCO3- = x

but pH = 3.44

pH = - log[H30+]

[H30+] = 10^-3.44 = 3.63x10^-4

[H30+] = 3.63x10^-4

Ka = [H3O+].[HCO3-] / [H2CO3]

[H30+] = x = 3.63x10^-4

[HCO3-] = 3.63x10^-4

[H2CO3] = 0.29 - x = 0.29 - 3.63x10^-4 = 0.289637

Ka = (3.63x10^-4)(3.63x10^-4)/0.289637 = 4.55x10^-7

6 0

3 years ago