All categories

3 years ago

How is Electric current able to flow?

2 answers:

3 0

Electric potential on one side of the closed circuit is applied and this causes the electrons to move to a position of lower potential. Imagine this as when you raise an object above the ground and release it. It moves from its higher potential energy position above the ground to its lower potential energy position.

AlekseyPX3 years ago

3 0

Explanation:

When the potential difference is provided to the conductor then the electrons start moving in the conductor. The electrons move from lower potential to the higher potential.

The rate of flow electrons constitutes the electric current. The direction of the electric current is opposite to the direction of the electrons.

For example, suppose the battery is connected to the circuit. It forces the electrons to flow in the conductor. The battery provides potential to the electrons so that the electrons can flow in the circuit. There are two terminals in the battery: Positive terminal and Negative terminal. Positive terminal is at higher potential. Negative terminal is at lower potential.

In this way, electrons flow in the circuit and constitute the electric current flow in the circuit.

You might be interested in

Which law is associated with inertia

N76 [4]

Answer:

The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

4 0

4 years ago

A single light beam is split into two equal beams, denoted a and b. beam a travels through a medium with a higher index of refra

nevsk [136]

Answer:

c) Both beams have the same wavelength.

4 0

2 years ago

Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 66.0 kg , is moving to the right at 2.00

ivann1987 [24]

Answer:

The velocity of skaters after collision is 0.55 m/s and they are moving to the left

Explanation:

Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.

Consider the velocity along right direction as positive while negative for left direction.

According to the problem,

Mass of first skater, m₁ = 66.0 kg

Mass of second skater, m₂ = 75.0 kg

Velocity of first skater, v₁ = + 2.00 m/s

Velocity of second skater, v₂ = -2.80 m/s

Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.

Applying conservation of linear momentum,

Momentum before collision = Momentum after collision

m₁v₁ + m₂v₂ = (m₁+m₂)v

Substitute the suitable values in the above equation.

66 x 2 - 75 x 2.8 = (66 + 75 )v

$v= \frac{-78}{141}$

v = -0.55 m/s

The negative sign denotes that both the skaters are moving in the left direction.

6 0

4 years ago

Standing on a bridge, you throw a stone straight upward. The stone hits a stream28.3 m below the point at which you release it2.

Helen [10]

Answer:

MISSING DATA, SPEED AT WHICH IT WAS LAUNCHED OR INITIAL

DISTANCE THAT REACHED UPWARDS

Explanation:

ANYWAY I LEAVE YOU THE LINK, AUÍ AHY MORE INFORMATION ON THE

SUBJECT.

https://gscourses.thinkific.com

4 0

3 years ago

A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015

vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

$N=\dfrac{1}{e}N_0$

$N_0$ = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

$T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s$

Using exponential decay formula

$N=N_0e^{\dfrac{-bt}{m}}$

Final amplitude = Initial times decay

$\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s$

The time taken is 33.33 seconds

7 0

3 years ago