Answer:
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Answer:
The force parallel to the horizontal is 26.24 N
Explanation:
She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle
), it has a force component on x (the horizontal, i will call this force
) and a force component on y (the vertical, i will call this
).
This can be seen in the attached picture.
Since we are asked about the force parallel to the horizontal, we need to find the component of the force
, since
is the adjacent angle, we need to use cosine:

since
and 



The force parallel to the horizontal is 26.24 N
Answer:
1.3m/s
Explanation:
Data given,
Mass,m=1.0kg,
Amplitude,A=0.10m,
Frequency,f=2.0Hz.
From the equation of a simple harmonic motion, the displacement of the object at a given time is define as

we can express the velocity by the derivative of the displacement,
Hence

at equilibrium, the velocity becomes

Hence if we substitute values we arrive at

Answer:
(a) 5.04 eV (B) 248.14 nm (c) 
Explanation:
We have given Wavelength of the light \lambda = 240 nm
According to plank's rule ,energy of light


Maximum KE of emitted electron i= 0.17 eV
Part( A) Using Einstien's equation
, here
is work function.
= 5.21 eV-0.17 eV = 5.04 eV
Part( B) We have to find cutoff wavelength



Part (C) In this part we have to find the cutoff frequency
