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lorasvet [3.4K]
3 years ago
10

Which of these statements would best explain the problem encountered with nuclear waste disposal? A) The isotopes have a long ha

lf-life and only remain radioactive for a long time period. B) The isotopes have a short half-life and only remain radioactive for a long time period. C) The isotopes have a long half-life and only remain radioactive for a short time period. D) The isotopes have a short half-life and only remain radioactive for a short time period. 
ANSWER IS A)
Physics
1 answer:
algol133 years ago
4 0
That's right, the correct answer is
<span>A) The isotopes have a long half-life and only remain radioactive for a long time period

The half life of an isotope is the time it takes for the amount of the sample to reduce to half of its initial value. If an isotope has a long half-life, it means it takes a long time to reduce down to a significant level, so it will remain radioactive for a long time period.</span>
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If a car is traveling at an average speed of 60 kilometers per hour, how long does it take to travel 12 kilometers?
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Answer: 0.2 hour

Explanation:

Speed = Distance / Time

Time = Distance / Speed

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3 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
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8 0
3 years ago
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PART a)

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here we can see that gravitational potential energy inversely varies with the distance

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Since we know that sum of kinetic energy and potential energy is constant here

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4 0
3 years ago
Which statement is correct about the car?
JulijaS [17]

Answer:

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