This is because leaves have air in the spaces between cells, which helps them collect CO2 gas from their environment to use in photosynthesis.
The correct answer to this question is 420 because it would be half of 741
About 25 percent of energy in an organism is used by the animal that eats it .
The balanced equation is as below
Na2CO3 +2 HCl → 2 NaCl +H2O + CO2
<u><em>Explanation</em></u>
step 1 : write the unbalanced chemical equation
that is Na2CO3 + HCl→ NaCl + H2O +CO2
Step 2: change the coefficient ( <em>number in front of chemical formula) </em>to make sure the number of atoms of an element are the same in both side.
By adding 2 in front of HCl and in front of NaCl balance the equation.
Therefore the balanced equation is as below
Na2CO3 +2HCl → 2NaCl +H2O +Co2
Answer:
2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂
Explanation:
The balanced reaction is:
Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:
- Pb(CH₃COO)₂: 1 mole
- H₂S: 1 mole
- CH₃COOH: 2 moles
- PbS: 1 mole
In this case, to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:
- H: 1 g/mole
- S: 32 g/mole
- Pb: 207 g/mole
The molar mass of the compounds are:
- H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
- PbS: 207 g/mole + 32 g/mole= 239 g/mole
So, by stoichiometry they react and are produced:
- H₂S: 1 mole* 34 g/mole= 34 g
- PbS: 1 mole* 239 g/mole= 239 g
Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?
mass of H₂S= 2.56 grams
<u><em>2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂</em></u>