Answer:

Explanation:
Given that,
The work function for silver is 4.73 eV.
We need to find the value of the work function from electron volts to joules.
We know that,

For 4.73 eV,

So, the work function for silver is
.
Answer:
92km
Explanation:
Given parameters:
Duration of the journey = 6hrs
Average speed = 58km/hr
Now, let us find the total distance of the journey;
Distance = Speed x time
Distance = 58 x 6 = 348km
So;
Average speed for the first 4hrs = 64km/hr
Time = 4hrs
Distance = 64 x 4 = 256km
For the rest of the journey, the student will cover;
= 348km - 256km
= 92km
Answer:
a. False
Explanation:
For an object to be moving at a constant velocity, a net force of 0 N would be required.
Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.
Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.
The answer to this question is A) False.
To solve the problem we will require the concept of Force as a definition of pressure and Area, and the concept of light pressure itself determined by the relationship between intensity and the speed at which light travels. We will match the terms and find the desired force value,

Here,
P = Pressure
A = Area
Pressure due to the light of the sun will be

Here,
I = Intensity
c = Speed velocity
Equation both therms we have that

We have a circular area then

Replacing with our values (Adding the radius of the Earth)


Therefore the Force on Earth due to radiation pressure is 
The phenomenon is called "refraction". It's the process of
light waves bending toward a different direction when they
cross a boundary between different media ... in this case,
from water into air.
Your brain doesn't know that the light waves bent toward a
new direction when they came out of the water into the air,
so your brain locates the bottom half of the pencil just like it
ALWAYS does ... in the direction the light waves are coming FROM.