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Harlamova29_29 [7]

3 years ago

8

Absorbance measurements in the range of a = 0.3-2 are considered the most accurate. why would absorbance measurements of 0.05 an

d 2.5 be considered inaccurate? select all that apply.

1 answer:

zhenek [66]3 years ago

6 0

Please provide the choices to select the possible choices.

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Many of the whales in the ocean rely upon tiny marine organisms, called plankton, for food. If all of the plankton suddenly died

exis [7]

Answer:

I believe the answer to be B.

Explanation:

Without food, the whales would die.

8 0

3 years ago

When did the ball fly farther—when it hit the moving bat or the bat that did not move?

8_murik_8 [283]

Answer:

when it hit the moving bat

Explanation:

force equals mass times acceleration which means the moving bat will add more force to the ball.

6 0

3 years ago

Do you divide mass by volume to get density

bogdanovich [222]

Density<span> is the </span>mass<span> of an object </span>divided<span> by its </span>volume<span>. So the answer would be Yes. Hope it helps! (:</span>

7 0

3 years ago

"What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.9 m and an e

notka56 [123]

Answer:

The Magnifying power of a telescope is $M = 109.26$

Explanation:

Radius of curvature R = 5.9 m = 590 cm

focal length of objective $f_{objective}$ = $\frac{R}{2}$

⇒ $f_{objective}$ = $\frac{590}{2}$

⇒ $f_{objective}$ = 295 cm

Focal length of eyepiece $f_{eyepiece}$ = 2.7 cm

Magnifying power of a telescope is given by,

$M = \frac{f_{objective} }{f_{eyepiece} }$

$M = \frac{295}{2.7}$

$M = 109.26$

therefore the Magnifying power of a telescope is $M = 109.26$

4 0

3 years ago

25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression

levacccp [35]

maximum speed of cheetah is

$v_1 = v_{max}$

speed of gazelle is given as

$v_2 = v_{g}$

Now the relative speed of Cheetah with respect to Gazelle

$v_{12} = v_1 - v_2$

$v_{12} = v_{max} - v_g$

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

$d = v_{12}* t$

so by rearranging the terms we can say

$t = \frac{d}{v_{12}}$

$t = \frac{d}{v_{max} - v_g}$

so above is the relation between all given variable

6 0

3 years ago