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Anni [7]
3 years ago
8

Using a refracting telescope, you observe the planet Mars when it is 1.95 × 10 11 m from Earth. The diameter of the telescope's

objective lens is 0.977 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 561 nm for the wavelength of light.
Physics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

The minimum feature size is 136.6 km.

Explanation:

It is given that,

Distance from planet Mars and Earth is, D=1.95\times 10^{11}\ m

Diameter of the objective lens, d = 0.977 m

We need to find the minimum feature size, on the surface of Mars that your telescope can resolve for you. The expression for resolving distance is given by :

y=\dfrac{1.22D\lambda}{d}\\\\y=\dfrac{1.22\times 1.95\times 10^{11}\times 561\times 10^{-9}}{0.977 }\\\\y=136603.78\ m\\\\y=136.6\ km

So, the minimum feature size is 136.6 km.

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Explanation:

<u>Given  :</u>

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The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next  

F=|F|cosФp            (1)

Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet  

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<em>As this force is in one direction, we could get its vector as next  </em>

F=(-4.8*10^22,0,0) N

F=(0,-4.8*10^22,0) N

F=(0,0-4.8*10^22) N

The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.

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