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Anni [7]
3 years ago
8

Using a refracting telescope, you observe the planet Mars when it is 1.95 × 10 11 m from Earth. The diameter of the telescope's

objective lens is 0.977 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 561 nm for the wavelength of light.
Physics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

The minimum feature size is 136.6 km.

Explanation:

It is given that,

Distance from planet Mars and Earth is, D=1.95\times 10^{11}\ m

Diameter of the objective lens, d = 0.977 m

We need to find the minimum feature size, on the surface of Mars that your telescope can resolve for you. The expression for resolving distance is given by :

y=\dfrac{1.22D\lambda}{d}\\\\y=\dfrac{1.22\times 1.95\times 10^{11}\times 561\times 10^{-9}}{0.977 }\\\\y=136603.78\ m\\\\y=136.6\ km

So, the minimum feature size is 136.6 km.

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horsena [70]

Answer:

a= g = - 9.81 m/s2.

The following equations will be helpful:

a = (vf - vo)/t d = vot + 1/2 at2 vf2 = vo2 + 2ad

When you substitute the specific acceleration due to gravity (g), the equations are as follows:

g = (vf - vo)/t d = vot + 1/2 gt2 vf2 = vo2 + 2gd

If the object is dropped from rest, the initial velocity ("vi") is zero. This further simplifies the equations to these:

g = vf /t d = 1/2 gt2 vf2 = 2gd

The sign convention that we will use for direction is this: "down" is the negative direction. If you are given a velocity such as -5.0 m/s, we will assume that the direction of the velocity vector is down. Also if you are told that an object falls with a velocity of 5.0 m/s, you would substitute -5.0 m/s in your equations. The sign convention would also apply to the acceleration due to gravity as shown above. The direction of the acceleration vector is down (-9.81 m/s2) because the gravitational force causing the acceleration is directed downward.

hope this info helps you out!

7 0
3 years ago
A ball rolls from point A to point B. The total energy of the ball at point A isn’t the same as the sum of its potential energy
murzikaleks [220]
B. Some of the ball’s energy is transformed to thermal energy.

Hope this helps you!
3 0
4 years ago
Read 2 more answers
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
Gnesinka [82]

Answer:

a).a_p=-2.39x10^{-12} rad/s^2

b).t=1016298.8 years

c).T_i=80.58x10^{-3}s

Explanation:

a).

The acceleration for definition is the derive of the velocity so:

a_p=\frac{dw}{dt}

w=\frac{2\pi}{t}

a_p=\frac{dw}{dt}=-\frac{2\pi}{t^2}*\frac{dT}{dt}

dT=0.0808s

dt=1 year*\frac{365d}{1year} \frac{24hr}{1d} \frac{60minute}{1hr} \frac{60s}{1minute}=31.536x10^{6}s

Replacing

a_p=-\frac{2\pi}{0.082s^2}*\frac{9.84x10^{-7}}{31.536x10^{6}s}= -2.39x10^{-12} rad/s^2

b).

If the pulsar will continue to decelerate at this rate, it will  stop rotating at time:

t=\frac{w}{a_p}

w=\frac{2\pi }{t}=\frac{2\pi }{0.0820s}=76.62 rad/s

t=\frac{76.62 rad/s}{2.39x10^{-12}rad/s^2}= 3.2058x10^{13}s

t=1016298.8 years

c).

582 years ago to 2019

1437

T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s

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4 years ago
The normal eye, myopic eye and old age
Leviafan [203]

Answer:

length f′0 when the eye is presbyopic and by a screen (the retina) at the distance d from the

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7 0
3 years ago
When 23Na is bombarded with protons, the products are 20Ne and A. a neutron B. an alpha particle C. a deuteron D. a gamma ray pa
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Answer:

The correct option is B. an alpha particle.

Explanation:

When ²³Na is bombarded with protons _{1}^{1}\textrm{H}, ²⁰Ne and one alpha particle _{2}^{4}\textrm{He} is released.

The reaction is as follows:

_{11}^{23}\textrm{Na} + _{1}^{1}\textrm{H} \rightarrow _{10}^{20}\textrm{Ne} + _{2}^{4}\textrm{He}

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.

5 0
4 years ago
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