<span>Rayed craters-</span><span> were the last features to form on the moon.</span>
Answer:
Explanation:
a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.
<h3>Longitudinal Waves:</h3>
- Longitudinal waves are waves in which particles moves in the direction parallel to the direction of wave.
- Longitudinal wave are one directional waves.
- Sound waves and tension force applied on spring are examples of longitudinal waves.
<h3>Transverse Waves:</h3>
- Transverse waves in which particles move perpendicular to the direction of wave propagation.
- Transverse wave are two directional waves.
- Ripples formed on water and all electromagnetic waves are examples of transverse waves.
Answer:
c. slow the flow of heat from inside the house to the outside.
Explanation:
Thermal insulation not completely stops the flow of heat but slow down the process of flowing of heat from inside the house to the outside.
Answer:
F=(-4.8*10^22,0,0) N
Explanation:
<u>Given :</u>
We are given the magnitude of the momentum of the planet and let us call this momentum (p_now) and it is given by p_now = 2.60 × 10^29 kg·m/s. Also, we are given the force exerted on the planet F = 8.5 × 10^22 N. and the angle between the planet and the star is Ф = 138°
Solution :
We are asked to find the parallel component of the force F The momentum here is not constant, where the planet moving along a curving path with varying speed where the rate change in momentum and the force may be varying in magnitude and direction. We divide the force here into two parts: a parallel force F to the momentum and a perpendicular force F' to the momentum.
The parallel force exerted to the momentum will speed or reduce the velocity of the planet and does not change its moving line. Let us apply the direction cosines, we could obtain the parallel force as next
F=|F|cosФp (1)
Where the parallel force F is in the opposite direction of p as the angle between them is larger than 90°. Now we can plug our values for 0 and I F I into equation (1) to get the parallel force to the planet
F=|F|cosФp
=-4.8*10^22 N*p
<em>As this force is in one direction, we could get its vector as next </em>
F=(-4.8*10^22,0,0) N
F=(0,-4.8*10^22,0) N
F=(0,0-4.8*10^22) N
The cosine of 138°, the angle between F and p is, is a negative number, so F is opposite to p. The magnitude of the planet's momentum will decrease.