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mrs_skeptik [129]
3 years ago
15

The first man jumps in his parachute Does not open. He accelerates at 10 m/s squared for four seconds before the parachute opens

how fast is he going just before the parachute opens
Physics
1 answer:
malfutka [58]3 years ago
4 0

The velocity of the parachutist after 4 seconds is 40 m/s (downward)

Explanation:

Before his parachute opens, the man is in free fall, so we can calculate its velocity at time t using the suvat equation:

v = u + at

where

v is the velocity at time t

u is the initial velocity

a=g=10 m/s^2 is the acceleration of gravity (taking downward as positive direction)

Assuming he jumps from rest,

u = 0

So, its velocity after t = 4 s is

v=0+(10)(4)=40 m/s

And the direction is downward, since the result is positive.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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