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Advocard [28]
3 years ago
14

A student is bouncing on a trampoline. at her highest point, her feet are 65 cm above the trampoline. when she lands, the trampo

line sags 15 cm before propelling her back up. part a for how long is she in contact with the trampoline?
Physics
1 answer:
Ede4ka [16]3 years ago
3 0
<span>she is in contact with the trampoline for less than one second.</span>
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PLZ HELP
ololo11 [35]
Potential energy= mass x gravity x height

m=25
g=9.8(on earth)
h=50

Ep= 25(9.8)(50)
Ep=12250 Joules
8 0
2 years ago
WILL MARK BRAINLIESTFor the simple harmonic motion equation d =4sin(8pit) what is the period?
shtirl [24]
The period of any wave is the time it takes for its angle
to go from zero to 2pi .

The 'sin' function is a wave.  The angle of this one is (8pi t).

When t=0, the angle is zero.
Wonderful.
Now, how long does it take for the angle to grow to 2pi ?

I*n other words, when is (8pi t) = 2pi ?

Divide each side by '2pi': . . . . . 4 t = 1

Divide each side by ' 4 ': . . . . . t = 1/4

And there you are.  Every time 't' grows by 1/4, (8pi t) grows by 2pi.
So if you graph this simple harmonic motion described by 'd', you'll
see the graph wiggle up and down with a period of 1/4 . 
4 0
3 years ago
Which color of light is diffracted at a greater angle from a diffraction grating, red or yellow light?
topjm [15]
The amount of diffraction depends on the wavelength of light, with shorter wavelengths being diffracted at a greater angle than longer ones (in effect, blue and violet<span> light are diffracted at a larger angle than is red light).

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
3 0
3 years ago
( Can someone help? )
Murrr4er [49]

Answer:

Answer would be 0.33

Explanation:

Calculations

8 0
3 years ago
Read 2 more answers
A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it
fomenos

Answer:68.15m/s

Explanation:

<u><em>Given: </em></u>

v₁=15m/s

a=6.5m/s²

v₁=?

x=340m

<u><em>Formula:</em></u>

v₁²=v₁²+2a (x)

<u>Set up:</u>

=\sqrt{15m/s} ^{2} +2(6.5m/s^2)(340m)

<h2><u><em>Solution:</em></u></h2><h2><u><em>68.15m/s</em></u></h2>

<u />

6 0
3 years ago
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