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Advocard [28]
3 years ago
14

A student is bouncing on a trampoline. at her highest point, her feet are 65 cm above the trampoline. when she lands, the trampo

line sags 15 cm before propelling her back up. part a for how long is she in contact with the trampoline?
Physics
1 answer:
Ede4ka [16]3 years ago
3 0
<span>she is in contact with the trampoline for less than one second.</span>
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An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is W/m². What is the rms
inn [45]

I think your question should be:

An industrial laser is used to burn a hole through a piece of metal. The average intensity of the light is

S = 1.23*10^9 W/m^2

What is the rms value of (a) the electric field and

(b) the magnetic field in the electromagnetic wave emitted by the laser

Answer:

a) 6.81*10^5 N/c

b) 2.27*10^3 T

Explanation:

To find the RMS value of the electric field, let's use the formula:

E_r_m_s = sqrt*(S / CE_o)

Where

C = 3.00 * 10^-^8 m/s;

E_o = 8.85*10^-^1^2 C^2/N.m^2;

S = 1.23*10^9 W/m^2

Therefore

E_r_m_s = sqrt*{(1.239*10^9W/m^2) / [(3.00*10^8m/s)*(8.85*10^-^1^2C^2/N.m^2)]}

E_r_m_s= 6.81 *10^5N/c

b) to find the magnetic field in the electromagnetic wave emitted by the laser we use:

B_r_m_s = E_r_m_s / C;

= 6.81*10^5 N/c / 3*10^8m/s;

B_r_m_s = 2.27*10^3 T

8 0
3 years ago
Read 2 more answers
Someone pls help fast
Kruka [31]
<h3>You forgot to add question...Add questions before asking so we can help</h3>
4 0
2 years ago
Read 2 more answers
A soccer ball is kicked from the ground with an initial speed of 19.3 m/s at an upward angle of 45°. a player 54.7 m away in the
dalvyx [7]

Hello there

the answer is

Let the initial position from where the ball is kickedat angle 45 deg, be A. The Horizontal range of the ball (AC) is V2 Sin2θ / g = 38.76 Meters

thank you

3 0
3 years ago
A dragster is traveling at a constant rate of 45 m/s. How fast is it going when it has traveled 325 m?
Sergeeva-Olga [200]

The speed of the dragster after travelling 325 m is still 45 m/s

Explanation:

In this problem, we are told that the dragster is travelling at constant rate, therefore its speed is constant and it is

v = 45 m/s

Therefore, its speed will remain constant during the entire motion: therefore, after having travelled for 325 m, its speed will still be 45 m/s.

We can also calculate the time taken for the dragster to cover the 325 m. In fact, the speed in a uniform motion is given by

v=\frac{d}{t}

where:

v is the speed

d is the distance covered

t is the time elapsed

In this case, we have:

v = 45 m/s

d = 325 m

Solving for t, we find:

t=\frac{d}{v}=\frac{325}{45}=7.2 s

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

6 0
3 years ago
Calcula la aceleración que se ha aplicado sobre una motocicleta si desde el reposo se ha elevado su velocidad a 100Km/h en 9s
N76 [4]

Answer:

Aceleracion= 3.09 m/sg2

Explanation:

MRUA = V=Vo+a•t

S=So+Vo•t+1/2a•t2

A= (100/3.6) / (9)

6 0
3 years ago
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