How many moles of al does 13.49 g of al represent?
1 answer:
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Answer:
r= 0.9949 (For 15,000)
r=0.995 (For 19,000)
Explanation:
We know that
Molecular weight of hexamethylene diamine = 116.21 g/mol
Molecular weight of adipic acid = 146.14 g/mol
Molecular weight of water = 18.016 g/mol
As we know that when adipic acid and hexamethylene diamine react then nylon 6, 6 comes out as the final product and release 2 molecule of water.
So
So
Mo= 226.32/2 =113.16 g/mol
Given that
Mn= 15,000 g/mol
So
15,000 = Xn x 113.16
Xn = 132.55
Now by using Carothers equation we know that
By calculating we get
r= 0.9949
For 19,000
19,000 = Xn x 113.16
Xn = 167.99
By calculating in same process given above we get
r=0.995
Answer:
There are 0.93 g of glucose in 100 mL of the final solution
Explanation:
In the first solution, the concentration of glucose (in g/L) is:
15.5 g / 0.100 L = 155 g/L
Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.
- 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)
The concentration of the second solution is:
So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:
1 L --------- 9.3 g
0.1 L--------- Xg
Xg = 9.3 g * 0.1 L / 1 L = 0.93 g