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kow [346]
3 years ago
12

A skeleton equation shows just the reactants and products whereas a balanced equation shows the

Chemistry
1 answer:
Anettt [7]3 years ago
8 0

Answer:

<u></u>

  • <em>A skeleton equation shows just the reactants and products whereas a balanced equation shows the</em><u> relative amounts of, or proportion between, reactants and products.</u>

Explanation:

The <em>skeleton equation</em> shows which <em>reactants </em>are being used and which <em>products </em>are being formed.

The reactants are shown on the left and the products are shown on the right side of the equations, separeted by an arrow.

For example, the skeleton equation to obtain water is:

  • H₂(g) + O₂(g) → H₂O (g)

From it you know that hydrogen and oxygen react to form water, yet you do not know in which ratio they do it.

Then, you balance the equation, adding the appropiate coefficients, to make the number of atoms of each kind on the reactant side equal to the number of the same kind of atoms on the product side.

This is, for the example of water, the number of hydrogen atoms on  the left must equal the number of atoms of hygrogen on the right side, and  the number of oxygen atoms of the left must equal the number of oxygen atoms on the right.

For the water example that is:

  • 2H₂(g) + O₂(g) → 2H₂O (g)

  • Showing that 2 molecuies of hydrogen (or 4 atoms) react with 1 molecule of oxygen (or 2 atoms) to produce 2 molecules of water, and that proportion (relative amounts) will always be true for that reaction.
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A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample
-BARSIC- [3]

Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) =  1 dm

Observed rotation (∝) = + 0.27°

Molarity = 0.175 M

Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1  dm ×  0.023275 g/mL )

= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

3 0
3 years ago
How many moles of oxygen gas can 0.882 mol of hydrogen peroxide produce if decomposition is complete? 2H2O2 (l) → 2H2O(l) + O2(g
andreyandreev [35.5K]
We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:

0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced

Hope this answers the question.
5 0
4 years ago
Read 2 more answers
A charged object (like a balloon that's been rubbed on the wall) cant attract an object with a net neutral charge (neither posit
UNO [17]

Answer: A balloon is charged by a process of frictional charging and the object is getting charged by the process of induction.

Explanation:

When two bodies are rubbed against each other, charging by friction or rubbing occurs. The electropositive object loses electrons to electronegative object. Thus, when balloon is rubbed on a wall, it becomes charged.

The charged balloon is able to attract an uncharged object by inducing charge on it without the two objects touching each other. Electrostatic force acts between two charged objects. Charged balloon causes electrons to move at one end thereby inducing opposite charge in the object and thus, charged balloon is able to attract uncharged object.

4 0
4 years ago
The ka of hypochlorous acid (hclo) is 3.0 ⋅ 10−8 at 25.0 °c. calculate the ph of a 0.0375m hypochlorous acid solution.
Scrat [10]
We can set up an ICE table for the reaction:                      
                      HClO          H+     ClO-
Initial              0.0375       0        0
Change         -x               +x      +x
Equilibrium    0.0375-x     x        x

We calculate [H+] from Ka:     
     Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)

Approximating that x is negligible compared to 0.0375 simplifies the equation to         
     3.0x10^-8 = (x)(x)/0.0375     
     3.0x10^-8 = x2/0.0375     
     x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9     
     x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.

We can now calculate pH:     
     pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
6 0
4 years ago
All of the following equations are statements of the ideal gas law except
evablogger [386]

Answer:

  • The first equation, <em>a. PV = nRT</em>, <u>is not</u> <em>a valid statement of the ideal gas law.</em>

Explanation:

The basic expression for the<em> ideal gas law</em> is:

  • pV=nRT      .......... [Equation 1]

Where:

  • n is the number of moles of the gas
  • V is the volume occupied by the gas
  • p is the pressure exerted by the gas molecules
  • T is the temperature in absolute scale (Kelvin)
  • R is the Universal gas constant (0.0821 atm-liter /K-mol or the equivalents in other units)

You can perform different algebraic operations to obtain equivalent equations:

<u>Choice b) Divide equation 1 by T and you get</u>:

  • pV / T = nR, which is the choice b. from your list.

<u>Choice c) Divide equation 1 by n × V and you get</u>:

  • p/n = RT / V, which is the choice c. from your list.

<u>Choice d) Divide equation 1  n × T and you get</u>:

  • pV / (nT) = R, which is the choice d. from your list.

The choice a. p = nRTV states that p and V are in direct relation, when the ideal gas law states that p and V are inversely related, so that equation is wrong.

<u>Conclusion: </u>the choice a, p = nRTV, is not a statement of the ideal gas law.

3 0
3 years ago
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