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kow [346]
3 years ago
12

A skeleton equation shows just the reactants and products whereas a balanced equation shows the

Chemistry
1 answer:
Anettt [7]3 years ago
8 0

Answer:

<u></u>

  • <em>A skeleton equation shows just the reactants and products whereas a balanced equation shows the</em><u> relative amounts of, or proportion between, reactants and products.</u>

Explanation:

The <em>skeleton equation</em> shows which <em>reactants </em>are being used and which <em>products </em>are being formed.

The reactants are shown on the left and the products are shown on the right side of the equations, separeted by an arrow.

For example, the skeleton equation to obtain water is:

  • H₂(g) + O₂(g) → H₂O (g)

From it you know that hydrogen and oxygen react to form water, yet you do not know in which ratio they do it.

Then, you balance the equation, adding the appropiate coefficients, to make the number of atoms of each kind on the reactant side equal to the number of the same kind of atoms on the product side.

This is, for the example of water, the number of hydrogen atoms on  the left must equal the number of atoms of hygrogen on the right side, and  the number of oxygen atoms of the left must equal the number of oxygen atoms on the right.

For the water example that is:

  • 2H₂(g) + O₂(g) → 2H₂O (g)

  • Showing that 2 molecuies of hydrogen (or 4 atoms) react with 1 molecule of oxygen (or 2 atoms) to produce 2 molecules of water, and that proportion (relative amounts) will always be true for that reaction.
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A container can hold 65g of water. circle the conversion factor needed to find the mass of water that 5 identical containers can
dezoksy [38]
Than you for posting your question here. I hope the answer helps. 

The answer as to be grams (g) since you it is aske for mass. What you have for units is 1/g. 

<span>Very close. The factor is 5. </span>
<span>answer is 5 * 65 g of water.</span>
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3 years ago
In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

  • Ca: 40 g/mole
  • F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

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