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Nina [5.8K]
3 years ago
14

What is the average atomic mass of an element with isotopes a b and c?

Chemistry
2 answers:
cestrela7 [59]3 years ago
5 0
Amm=(%of a × mass of a + %of b ×mass of b +%of c × mass of c)/100
vesna_86 [32]3 years ago
4 0

Answer:

Average Atomic Mass of the Isotope = [ Percentage of <em>a </em>in mass spectrum x corresponding atomic mass of <em>a</em> + Percentage of <em>b </em>in mass spectrum x corresponding atomic mass of <em>b</em> + Percentage of <em>c </em>in mass spectrum x corresponding atomic mass of <em>c </em>]

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Why are ionic compounds solids
enot [183]

Answer: The crystal structure of ionic compounds is strong and rigid. It takes a lot of energy to break all those ionic bonds. As a result, ionic compounds are solids with high melting and boiling points.

7 0
3 years ago
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How many moles are there in 17.6g NaOH?
Taya2010 [7]

Answer:

The answer is 39.99711. We assume you are converting between grams NaOH and mole. You can view more details on each measurement unit: molecular weight of NaOH or mol This compound is also known as Sodium Hydroxide.

5 0
2 years ago
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A prescription medication requires 0.00255g per lb of body weight.
Pani-rosa [81]

The prescription in mg/Kg of body weight is 5.62 mg/kg.

<h3>How to convert to mg required per kg of body weight?</h3>

Drugs are chemicals that are taken into the body and they are able to help to correct anomalies in the bodies. Drugs are taken according to the kind of ailment that a person is suffering from.

The nature of the drug and the severity of thee ailment of the person determines the dose of the drug.

Now we know that;

1 g/pound =2204.6244 mg/kg

0.00255g/lb = 0.00255g/lb * 2204.6244 mg/kg/1 g/pound

= 5.62 mg/kg

Learn more about unit conversion:brainly.com/question/4736731

#SPJ1

Missing parts;

A prescription medication requires 0.00255 g per lb of body weight.  Convert this quantity to the number of mg required per kg of body weight.

5 0
1 year ago
Which techniques would be best for separating the solute from the solvent in a solution
grin007 [14]

Answer:

depending on the solvent, evaporation would be the easiest

3 0
3 years ago
A sample of carbon dioxide occupies a volume of 2.50L liters at 300kPa pressure and a temperature 273K. What pressure would the
Drupady [299]

Answer:

The answer to your question is:    P2 = 846 kPa

Explanation:

Data

V1 = 2.5 l

P1 = 300 kPa

T1 = 273 °K

P2 = ?

V2 = 1 l

T2 = 308°K

Formula

             \frac{P1V1}{T1}  = \frac{P2V2}{T2}

             P2 = \frac{P1V1T2}{T1V2} \\

             P2 = \frac{(300)(2.5)(308)}{(273)(1)} \\

            P2 = \frac{231000}{273} \\

            P2 = 846 kPa

5 0
3 years ago
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