Answer:
3.6 × 10⁵ N/C = 360 kN/C
Explanation:
Let R = 2.0 cm be the radius of the sphere and q = -8.0 nC be the charge in it. Let q₁ be the charge at radius r = 1.0 cm. Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πr³
q₁ = q(r/R)³. The electric field due to q₁ at r is E₁ = kq₁/r² = kq(r/R)³/r² = kqr/R³
The electric field due to the point charge q₂ = 5.0 nC is E₂ = kq₂/r².
So, the magnitude of the total electric field at r = 1.0 cm is
E = E₁ + E₂ = kqr/R³ + kq₂/r² = k(qr/R³ + q₂/r²)
E = 9 × 10⁹(-8 × 10⁻⁹ C × 1 × 10⁻² m/(2 × 10⁻² m)³ + 5 × 10⁻⁹ C/(1 × 10⁻² m)²)
E = 9 × 10⁹(-1 × 10⁻⁵ + 5 × 10⁻⁵)
E = 9 × 10⁹(4 × 10⁻⁵)
E = 36 × 10⁴ N/C = 3.6 × 10⁵ N/C = 360 kN/C
Answer:
36 joule
Explanation:
The formula of kinetic energy is 1/2 mv2.
Answer:
The current drawn by the motor from the line is 4.68 A.
Explanation:
Given that,
Internal resistance of the dc motor, r = 3.2 ohms
Voltage, V = 120 V
Emf in the motor,
We need to find the current drawn by the motor from the line. A dc motor with its rotor and field coils connected in series, applying loop rule we get :
I is current drawn by the motor
So, the current drawn by the motor from the line is 4.68 A. Hence, this is the required solution.
The Kinetic Energy (KE) is calculated using the formula:
KE = 0.5 m v^2
Where,
m = mass of bare helium nucleus = 6.64 ✕ 10^−27 kg
v = velocity = 0.018 c = 0.018 * 3 ✕ 10^8 m / s^2 = 5.4 ✕ 10^6
m / s^2
Calculating:
KE = 0.5 (6.64 ✕ 10^−27
kg) (5.4 ✕ 10^6 m / s^2)^2
KE = 9.68✕<span> 10^−14
J</span>