Answer is: mass of slaked lime is 6.92 grams.
Balanced chemical reaction: Ca(OH)₂ + 2NH₄Cl → CaCl₂ + 2NH₃ + 2H₂O.
m(NH₄Cl) = 10 g; mass of ammonium chloride.
M(NH₄Cl) = 14 + 1·4 + 35.5 · g/mol.
M(NH₄Cl) = 53.5 g/mol; molar mass of ammonium chloride.
n(NH₄Cl) = m(NH₄Cl) ÷M(NH₄Cl).
n(NH₄Cl) = 10 g ÷ 53.5 g/mol.
n(NH₄Cl) = 0.187 mol; amount of ammonium chloride.
From balanced chemical reaction: n(NH₄Cl) : n(Ca(OH)₂) = 2 : 1.
n(Ca(OH)₂) = 0.093 mol.
m(Ca(OH)₂) = n(Ca(OH)₂) · M(Ca(OH)₂).
m(Ca(OH)₂) = 0.093 mol · 74.1 g/mol.
m(Ca(OH)₂) = 6.92 g.
Answer: days
Explanation: controlled variable is that they put it in 2 jars for 2 days one with a lid and one with no lid. dependent is how long it was there (2) days. Independent is you left it in one place for the whole 2 days. i think.
Nucleic acids typically contain phosphorous as well as nitrogen. The proteins, being made up a diverse set of amino acids, have, in addition to carbon, hydrogen, oxygen, and nitrogen, the elements sulfur and selenium.
Mg (s) + 2 HCl (aq) -> MgCl2 (aq) + H2 (g)
1) Number of mols of HCl, n
n = 6.3 L * 4.5 mol/L = 28.35 mol
2) ratio: 2 mol HCl / 1 mol Mg = 28.35 mol HCl / x mol Mg
x = 28.35 mol HCL * 1 mol Mg / 2 mol HCL = 14.175 mol Mg
3) Convert mol to mass using atomic mass of Mg
14.175 mol Mg * 24.3 g Mg / mol Mg = 344. 45 g
Answer: 344.45 g
Answer:
the number of laps in the case when he run for 50 minutes is 18,333.33
Explanation:
The computation of the number of laps in the case when he run for 50 minutes is shown below:
Given that
He runs 440m lap in 1.2 minutes
So in 50 minutes he can have laps of
= 440 × 50 ÷ 1.2
= 18,333.33 laps
hence, the number of laps in the case when he run for 50 minutes is 18,333.33
