If they lose an electron, that means they become more positive since an electron is negatively charged. So the answer is ‘positive’
We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
Answer:
1.) Frequency F = 890.9 Hz
2.) Wavelength (λ) = 0.893 m
Explanation:
1.) Given that the wavelength = 0.385m
The speed of sound = 343 m / s
To predict the frequency, let us use the formula V = F λ
Where (λ) = wavelength = 0.385m
343 = F × 0.385
F = 343/0.385
F = 890.9 Hz
2.) Given that the frequency = 384Hz
Using the formula again
V = F λ
λ = V/F
Wavelength (λ) = 343/384
Wavelength (λ) = 0.893 m
The two questions can be solved with the use of formula
