V = frequency * wavelength
v = 80 * 4
v = 320m/s
Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
Speed of Ferry is towards North with magnitude 6.2 m/s
Here if we assume that North direction is along Y axis and East is along X axis then we can say
Now a person walk on ferry with speed 1.5 m/s towards east with respect to Ferry
so it is given as
also by the concept of relative motion we know that
now plug in all values in it
now if we need to find the speed of the person then we need to find its magnitude
so it is given as
Refractive index of a medium = speed of light in vacuum
-------------------------------------
speed of light in that medium
Answer:
v₀ₓ = 14.34 m / s
Explanation:
We can solve this problem using the projectile launch equations.
Let's look for the time it takes to descend to the height of the cave
y = t - ½ g t²
As it rises horizontally the initial vertical speed is zero
y = 0 - ½ gt²
t = √2 y / g
t = √2 7.3 / 9-8
t = 1.22 s
This is the same time to cross the ravine
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 17.5 / 1.22
v₀ₓ = 14.34 m / s
This is the minimum speed.