Answer:
The magnitude of the change in linear momentum of the ball is 6 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 1 kg
Initial sped of the ball, u = 3 m/s
It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s
The magnitude of the change in linear momentum of the ball is given by :
So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.
The answer should be A or D
Answer;
A legislative body oversees city departments directly.
Explanation;
City commission government is a form of local government in the United States. In a city commission government, voters elect a small commission, typically of five to seven members, on a plurality-at-large voting basis.
The commissioners constitute the legislative body of the city and, as a group, are responsible for taxation, appropriations, ordinances, and other general functions.
Explanation:
Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.
Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume. However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.
Since we are talking about the relation between the velocity and the time, the distance must be given.
Since no distance is given here, then I'll just tell you how to solve this question in terms of equations and you can substitute with the numbers you have.
The velocity can be calculated using the following rule:
velocity = distance / time
we are given the time as 3.5 seconds, therefore:
velocity = distance / 3.5
