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Licemer1 [7]
3 years ago
10

Consider the proportionality below.

Chemistry
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

c.) ideal gas law

Explanation:

just took test

hope this helps!!!

svet-max [94.6K]3 years ago
4 0

Answer:

Ideal gas law

Explanation:

The expression is the ideal gas law when properly written;

              PV = nRT

where P is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the gas constant

T is the temperature

The ideal gas law is derieved from the three major gas laws;

--- Boyle's law, Charles's law and Avogadro's law

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A solution in which the maximum amount of solute is dissolved is said to be
ivanzaharov [21]

Saturated.

An unsaturated solution is a solution where more solute can still be added.

5 0
3 years ago
Calculate the freezing point of a solution 1.25 g benzene (C6H6) in 125 g of chloroform (CHCl3).
posledela

Answer:

The freezing point for the solution is -64.09°C

Explanation:

This problem can be solved, by the freezing point depression. This colligative problem shows, that the freezing point of a solution is lower than the freezing point of pure solvent.

ΔT = Kf.  m

ΔT = T° freezing pure solvent - T° freezing solution

Kf = Cryscopic constant, for chloroform is 4.68

T°freezing pure solvent = -63.5°C

m is mol/kg of solvent → molality

Let's determine the moles of benzene

1.25 g / 78 g/mol = 0.0160 mol

Let's convert the mass of solvent to kg

125 g . 1kg / 1000 g = 0.125 kg

m = 0.0160 mol / 0.125 kg → 0.128 m

Let's go to the formula to replace the data

-63.5°C - T° freezing solution = 4.68 °C/m . 0.128 m

T° freezing solution = - (4.68 °C/m . 0.128 m + 63.5°C)

T° freezing solution = - 64.09°C

3 0
3 years ago
HELP PLEASE
Phoenix [80]

<u>mass of reactants = mass of products</u> best represents the law of conservation of mass

Explanation:

This is a law of thermodynamic that applies to chemical reactions. The mass of the reactants must equal to that of the products because energy/mass cannot be destroyed or created. This is why ideally, chemical reactions should be balanced to conform to this law.

8 0
3 years ago
Which of the following must be true about a reaction if it is only spontaneous at high temperatures?
Anastaziya [24]

1) Answer is: It is endothermic, with both positive enthalpy and entropy changes.

Endothermic reactions (ΔH>0) that increase the entropy of the system (ΔS>0) are spontaneous at high temperatures.

The change in Gibbs free energy (ΔG), at constant temperature and pressure, is: ΔG=ΔH−TΔS.

ΔH is the change in enthalpy.

ΔS is change in entropy.

T is temperature of the system.

When ΔG is negative, a reaction (occurs without the addition of external energy) will be spontaneous (exergonic).

2) Answer is: It is endothermic and heat is added to the system.

There are two types of reaction:

1) endothermic reaction (chemical reaction that absorbs more energy than it releases, ΔH>0).

2) exothermic reaction (chemical reaction that releases more energy than it absorbs).

For example, the breakdown of ozone is an endothermic process. Ozone has lower energy than molecular oxygen (O₂) and oxygen atom, so ozone need energy to break bond between oxygen atoms.

3) Answer is: For every two AB produced, the reaction requires three A.

Balanced chemical reaction: 3A + B → 2AB.

From balanced chemical reaction: n(A) : n(AB) = 3 : 2.

n(A) = 3 · n(AB) ÷ 2.

A and B are reactants and AB is product of balanced chemical reaction.

For every two AB produced, the reaction requires one B.

4) Answer is:

the amount of required activation energy = potential energy of the B - potential energy of the reactants A.

the enthalpy change of the reaction = potential energy of the products C - potential energy of the reactants A.

For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start).

This is endothermic reaction.

3 0
3 years ago
You are carefully watching the temperature of your melting point apparatus as it is heating up. At 132 C it is still a white sol
Lisa [10]

Answer:

See the answer below

Explanation:

<em>Since the experiment is set out to determine the melting point of the white solid, after missing the melting point due to distraction, there are two possible solutions and both involves a repeat of the experiment.</em>

1. The first one is to allow the molten substance to solidify again and then repeat the experiment. This time around, a critical attention should be paid to be able to notice the melting point temperature once the temperature gets to 132 C.

2. The second solution would be discard the molten substance and repeat the experiment with the a new solid one. Similarly, critical attention should be paid once the temperature gets to 132 C since it is sure that the melting point lies within 132 and 138 C.

6 0
3 years ago
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