<span>PV = nRT
(4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K)
n = 1.08 moles
28 g/mol, 1.08 moles = 30.3 grams
your answer is
C.30.3 g</span>
Answer:
V₂ = 1.86 L
Explanation:
Given data:
Initial volume = 4.30 L
Initial pressure = 1 atm
Initial temperature = 273.15 K
Final temperature = 302 K
Final volume = ?
Final pressure = 2.56 atm
Solution:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂
/T₁ P₂
V₂ = 1 atm ×4.30 L × 302 K / 273.15 K × 2.56 atm
V₂ = 1298.6 atm.L.K / 699.26 K.atm
V₂ = 1.86 L
Answer:
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Explanation:
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Answer:
The correct answer to this question is (c) 25.0 m
Explanation:
To solve this we list out the variables thus
mole fraction of sodium hydroxide = 0.310
Mole fraction = number of moles of a component ÷ total number of moles in the solution
Mole fraction = 0.310
In a saturaturated aqueous solution we have NaOH and water
∴ Number of moles of water molecules per unit = 1 - 0.310 = 0.690
However 0.690 moles of H₂O weighs = 0.690 mole × 18.01528 g/mol =12.43 g = 0.01243 kg of H₂O
But the molality = number of moles per Kilogram of H₂O
therefore molality of NaOH in the sample of solution =
(0.310 mol of NaOH )÷(0.01243 kg of H₂O)
= 24.93 mol/kg or ≅ 25.0 m
