Answer:
(a) Option B
The magnitude of the buoyancy force is equal to that of the ball's weight.
(b) Option B
The magnitude of the buoyancy force is larger than that of the ball's weight.
(c) Option B
They both have the same buoyancy force.
Explanation:
(a)
Ball 1
The sum of vertical forces is zero hence therefore
B-mg=0 where B is buoyancy force, m is mass of ball, g is acceleration due to gravity
B=mg
mg is weight of ball
Therefore, option B, The magnitude of the buoyancy force is equal to that of the ball's weight
(b)
Ball 2
The sum of vertical forces is zero hence therefore
B-T-mg=0 where B is buoyancy force, m is mass of ball, g is acceleration due to gravity and T is tension in the string
B=mg+T
Therefore, option B, The magnitude of the buoyancy force is larger than that of the ball's weight.
(c
)
Ball 2 and 3
They have similar buoyancy force since the weight displaced by the body equals the buoyancy force. In this case, the weight of the displaced fluid is proportional to the volume of the ball since the two balls have same volume. It therefore means that their buoyancy forces are also the same.
Answer:
Tension in the wire= 1837.5 N
Explanation:
The answer along with solution can be found in the image attached.
The correct answer is option ( A) the ratio of their average speeds (bird 1/bird 2) is 1.0
velocity = distance / Time
Let us assume distance covered by Bird 1 = d
case 1 (Bird 1) :-
time = 6 hours
velocity(Bird1) = d/6 = 0.167*d
case 2 (Bird 2) :-
time = 12 hours
distance is twice of Bird 1 = 2d
velocity(Bird2) = 2d/12 = 0.167*d
now, velocity of Bird1/Bird2 = (0.167*d)/(0.167*d) = 1.0
So,velocity of (Bird1/Bird2) is 1.0 .
Average velocity / Average speed = Total displacement / Total distance. Remember that the numerator is less than or equal to the denominator. As a result, the ratio is always equal to or less than one. Distance traveled divided by time taken is the most commonly used formula for calculating average speed. The other formula is to add the initial and final speeds together and divide by two.
Learn more about average speeds here :-
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