1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)
Ksp{Zn(OH)₂}=1.2*10⁻¹⁷
2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)
Ksp{Zn(CN)₂}=2.6*10⁻¹³
Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}
Zn(OH)₂ precipitates first
It takes the Earth 24 hours to rotate on its axis and this rotation is what causes there to be days and nights.
We will get the molality from this formula:
Molality = no.of moles of solute / Kg of solvent
So first we need the no.of moles of KNO3 = the mass of KNO3 / molar mass of KNO3
no.of moles of KNO3 = 175 / 101.01 = 1.73 mol
By substitution in the molality formula:
∴ molality = 1.73 / (750/1000) = 2.3 Molal
Answer:
first option is not true
Explanation:
1 mole = 6.02 × 10²³ particles
C3H8 has 1 mole, so has 6.02 × 10²³ particles
5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles
3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles
4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles
