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Artemon [7]
3 years ago
5

Solve the inequality.-4X 824 (X 4)-8O A) X 2-4O B) X 4O C) X 4O D) X 4

Mathematics
1 answer:
hjlf3 years ago
6 0
-4x+8 \geq 4(x-4)-8 \\ -4x+8 \geq 4x-16-8 \\ -4x+8 \geq 4x-24 \\ -4x-4x \geq -24-8 \\ -8x \geq -32 \\ x \leq  \frac{-32}{-8}  \\ x \leq 4
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What is the sum of an 8-term geometric series if the first term is −11, the last term is 859,375, and the common ratio is −5? −1
LekaFEV [45]

Answer:

The sum of geometric series is 716144

Step-by-step explanation:

Given

First term=a_1= -11

Last term=a_8=859375

Common ration of geometric series=r= -5

And

Total terms in geometric sequence=n=8

We know that the formula for sum of geometric series is:

S_n=  (a_1 (1-r^n))/(1-r)

=  (-11(1-(-5)^8)/(1-(-5))

=  (-11(1-5^8))/(1+5)

=  (-11(1-390625))/6

=(-11(-390624)))/6

=4296864/6

=716144

So the sum of geometric series is: 716144  ..

4 0
3 years ago
THE AP CALCULUS EXAM SCORES WERE RELEASED IN JULY. THE SECONDARY MATH SPECIALIST PREPARED THE BOX PLOT SHOWN TO PRESENT THE SCOR
Ganezh [65]

Answer : option A

To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile

Inter quartile range is the middle 50% of the given range of scores.

The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%

From the diagram , we can see that

Upper quartile = 89

lower quartile = 65

So range is 65%  to 89%

8 0
4 years ago
3- Product of two expressions H.C.F=<br>A. H.CF<br>B. L.C.M<br>C. H.C.F + L.C.M<br>D. H.C.P x L.C.M​
Mnenie [13.5K]

(i) The product of the two expressions is equal to the product of their factors. (ii) The product of the two expressions is equal to the product of their H.C.F. and L.C.M. 2.

8 0
3 years ago
How many answers does –2(3x – 1) = –6x – 1 have
GaryK [48]

Answer:

it has 3 steps

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
Expand &amp; simplify<br> 3(t+5)+5(t−6)
Reptile [31]

Answer:

8t - 15

Explanation:

⇒ 3(t+5)+5(t−6)

distribute inside parenthesis

⇒ 3(t) + 3(5) + 5(t) + 5(-6)

multiply the variables

⇒ 3t + 15 + 5t - 30

collect like terms

⇒ 3t + 5t + 15 - 30

add/ subtract like terms

⇒ 8t - 15

6 0
2 years ago
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