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2 years ago

Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?

Chemistry

1 answer:

Luba_88 [7]2 years ago

7 0

Answer:

Yes, all titrations of a strong base with a strong acid have the same pH at the equivalence point.

This pH is 7.

Explanation:

Strong acids and strong bases ionize completely in aqueous solutions. The ionization of strong acids produce hydronium ions, H₃O⁺, and the ionization of strong bases produce hydroxide ions, OH⁻.

Since the ionization of strong acids and bases progress until completion, there is not reverse reaction.

The definition of pH is pH = - log [H₃O⁺]. Acids have low pH (below 7, and greater than 0) and bases have high pH (above 7 and less than 14). Neutral solutions have pH = 7.

Acid-base titrations are a method to determine the concentration of an acid from the known concentration of a base, or the concentraion of a base from the known concentration of an acid.

The equivalence point of the titration is the point at which the the number of moles of hydronium ions and hydroxide ions are equal.

Then, at that point, the hydronium and hydroxide ions will be in the stoichiometric proportion to form a neutral solution, i.e. the pH of the solution wiill be 7.

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2. Energy cost of plasma generation of NO, NO2, and NO3 in air (or air bubble) is about 20 eV per N-atom. 100 W plasma system ha

svet-max [94.6K]

Answer:

0.0933 moles/Litre

Explanation:

We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:

Energy cost = $\frac{20ev}{N- atom}$

Given that:

Energy = 100 W for 60 minutes

100 W = 100 J/s

= 100 J/s × (60 × 60) seconds

= 3.6 × 10⁵ J

Let now convert 3.6 × 10⁵ J to eV; we have:

= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV

= 2.247 × 10²⁴ eV

So, number of N-atom used up to form compounds will now be:

= 2.247 × 10²⁴ eV × $\frac{1}{20eV} N-atom$

= 1.123 × 10²³ N-atom

To moles; we have:

= $\frac {1.123*10^{23}} {6.023*10^{23}}$

= 0.186 moles

However, we are expected to leave our answer in concentration (i.e in moles/L)

since we are given 2L

So; 0.186 moles ⇒ $\frac{0.186 moles}{2 Litre}$

= 0.0933 moles/Litre

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Answer:

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Explanation:

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mafiozo [28]

Answer:

Most similar ----- Lithium

Least similar ---- Nitrogen

Explanation:

Cesium is an element on the periodic with the atomic number 133. It lies in group 1 (i.e., the alkali metals) and period 6 on the periodic table. The oxidation state of group 1 metals is +1. Cesium forms an oxide with oxygen as $Cs_2O$ .

The most similar compound to this chemical compound is Lithium because Lithium happens to be in the same group one metal with Cesium and forms the compound $Li_2O$ with the oxygen

The least similar compound nitrogen due to fact that it is an oxide that is covalent in nature and lies between-group 3 -17 to form an $NO_2$ with oxygen.

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2 years ago

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Juli2301 [7.4K]

Answer:

False

Explanation:

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2 years ago

How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?

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