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3 years ago

Do all titrations of a strong base with a strong acid have the same ph at the equivalence point?

Chemistry

1 answer:

Luba_88 [7]3 years ago

7 0

Answer:

<u>Yes,</u> <em>all titrations of a strong base with a strong acid have the same pH at the equivalence point.</em>

This <u>pH is 7.</u>

Explanation:

<em>Strong acids</em> and <em>strong bases</em> ionize completely in aqueous solutions. The ionization of strong acids produce hydronium ions, H₃O⁺, and the ionization of strong bases produce hydroxide ions, OH⁻.

Since the ionization of strong acids and bases progress until completion, there is not reverse reaction.

The definition of pH is pH = - log [H₃O⁺]. Acids have low pH (below 7, and greater than 0) and bases have high pH (above 7 and less than 14). Neutral solutions have pH = 7.

Acid-base titrations are a method to determine the concentration of an acid from the known concentration of a base, or the concentraion of a base from the known concentration of an acid.

The<em> equivalence point</em> of the titration is the point at which the the number of moles of hydronium ions and hydroxide ions are equal.

Then, at that point, the hydronium and hydroxide ions will be in the stoichiometric proportion to form a neutral solution, i.e. the pH of the solution wiill be 7.

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Write a balanced equation for the single-replacement oxidation-reduction reaction described, using the smallest possible integer

jeyben [28]

Answer:

$\rm Cl_2 + 2\; KBr \to Br_2 + 2\; KCl$ .

One chlorine molecule reacts with two formula units of (aqueous) potassium bromide to produce one bromine molecule and two formula units of (aqueous) potassium chloride.

Explanation:

<h3>Formula for each of the species</h3>

Start by finding the formula for each of the compound.

Both chlorine $\rm Cl$ and bromine $\rm Br$ are group 17 elements (halogens.) Each
On the other hand, potassium $\rm K$ is a group 1 element (alkaline metal.) Each

Therefore, the ratio between $\rm K$ atoms and $\rm Br$ atoms in potassium bromide is supposed to be one-to-one. That corresponds to the empirical formula $\rm KBr$ . Similarly, the ratio between

The formula for chlorine gas is $\rm Cl_2$ , while the formula for bromine gas is $\rm Br_2$ .

<h3>Balanced equation for the reaction</h3>

Write down the equation using these chemical formulas.

$\rm ?\; Cl_2 + ?\; KBr \to ?\;Br_2 + ?\; KCl$ .

Start by assuming that the coefficient of compound with the largest number of elements is one. In this particular equation, both $\rm KBr$ and $\rm KCl$ features two elements each.

Assume that the coefficient of $\rm KCl$ is one. Hence:

$\rm ?\; Cl_2 + 1 \; KBr \to ?\;Br_2 + ?\; KCl$ .

Note that $\rm KBr$ is the only source of $\rm K$ and $\rm Br$ atoms among the reactants of this reaction.

There would thus be one $\rm K$ atom and one $\rm Br$ atom on the reactant side of the equation.

Because atoms are conserved in a chemical equation, there should be the same number of $\rm K$ and $\rm Br$ atoms on the product side of the equation.

In this reaction, $\rm Br_2$ is the only product with $\rm Br$ atoms.

One $\rm Br$ atom would correspond to $0.5$ units of $\rm Br_2$ .

Similarly, in this reaction, $\rm KCl$ is the only product with $\rm K$ atoms.

One $\rm K$ atom would correspond to one formula unit of $\rm KCl$ .

Hence:

$\displaystyle \rm ?\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl$ .

Similarly, there should be exactly one $\rm Cl$ atom on either side of this equation. The coefficient of $\rm Cl_2$ should thus be $0.5$ . Hence:

$\displaystyle \rm \frac{1}{2}\; Cl_2 + 1 \; KBr \to \frac{1}{2}\;Br_2 + 1\; KCl$ .

That does not meet the requirements, because two of these coefficients are not integers. Multiply all these coefficients by two (the least common multiple- LCM- of these two denominators) to obtain:

$\displaystyle \rm 1\; Cl_2 + 2 \; KBr \to 1\;Br_2 + 2\; KCl$ .

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3 years ago

Balance the following redox reaction in acidic solution: H+(aq)+Zn(s)→H2(g)+Zn2+(aq)

erma4kov [3.2K]

2H⁺(aq) + Zn(s) ----> H2(g) + Zn²⁺(aq)

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</span>2H⁺(aq) + Zn(s) -----> H2(g) + Zn²⁺

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3 years ago

Which statement describes solstices?

vodka [1.7K]

I believe it is the very first one

hope it helps :)

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3 years ago

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Kruka [31]

Answer:

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