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2 years ago

When someone opens a bottle of carbonated drinks, the pressure inside the bottle decreases.

Chemistry

1 answer:

Mekhanik [1.2K]2 years ago

8 0

Answer:

When you open the bottle, there is a dramatic decrease in pressure over the liquid, so the CO2 starts to leave the liquid very rapidly, causing the mass exodus of gas, or "explosion" of bubbles. This also explains why soda goes flat.

Explanation: HOPE THIS HELPS YOU..

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Which of the following chemical reactions will produce a precipitate? *

Zolol [24]

Answer:

Explanation:

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3 years ago

The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.

lara [203]

Answer:

This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.

Now calculate the moles of each reactant:

Moles Fe2O3: 16.0 g/159.7 g/mole = 0.100 moles Fe2O3

Moles Al: 8.1 /26.98 g/mole = 0.300 moles Al

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al. (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

Which of the two reactants is the limiting reagent?

We have more than enough moles of Al to react with 0.10 moles of Fe2O3. (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3. Fe2O3 is the limiting reagent.

Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed. Since Fe2O3 is the limiting reagent, we will assume that it completely reacts. That means 0.1 moles of Fe2O3 is reacted. Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe. At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

5 0

1 year ago

Please Help!

Whitepunk [10]

We can use two equations for this problem.

t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half-life of the element and λ is decay constant.

20 days = 0.693 / λ
λ = 0.693 / 20 days (1)

Nt = Nο eΛ(-λt) (2)

Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time taken.
t = 40 days

No = 200 g

From (1) and (2),
Nt = 200 g eΛ(-(0.693 / 20 days) 40 days)
Nt = 50.01 g

Hence, 50.01 grams of isotope will remain after 40 days.

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3 years ago

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Alenkinab [10]

Answer:

Explanation:

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3 years ago

It is possible to have more than the maximum amount of solute dissolved in a solvent.

vladimir1956 [14]

B. False

When the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is saturated with solute.

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3 years ago

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