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BabaBlast [244]
3 years ago
6

What is meant by the statement that you don’t “own” the atoms that make up your body?

Physics
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

there are as many atoms in a normal breath of air as there are breathfuls of air in the atmosphere of the world

Explanation:

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How much total heat transfer is necessary to lower the temperature of 0.175 kg of steam from 125.5 °C to −19.5 °C, including the
GaryK [48]

Answer:

Explanation:

The heat required to change the temperature of  steam from 125.5  °C to 100 °C is:

Q_1 = ms_{steam} (125.5^0C - 100^0C) \\ \\ Q_1 = 0.175 \ kg ( 1520 \ J/kg.K ) (25.5^0 \ C) \\ \\ Q_1 = 6783 \ J

The heat required to change the steam at 100°C to water at 100°C is;

Q_2 = mL_v \\ \\ Q_2 = (0.175 \ kg) (2.25*10^6 \ J/kg ) \\ \\ Q_2 = 393750 \ J

The heat required to change the temperature from 100°C to 0°C is

Q_3 = ms_{water} (100^) \ C) \\ \\ Q_3 = (0.175\ kg)(4186 \ J/kg.K) (100 ^0c ) \\ \\ Q_3 = 73255 \ J

The heat required to change the water at 0°C to ice at 0°C  is:

Q_4 = mL_f \\ \\ Q_4 = (0.175 \ kg)(3.34*10^5 \ J/kg) \\\\ Q_4 = 58450 \ J

The heat required to change the temperature of ice from 0°Cto -19.5°C is:

Q_5 = ms _{ice} (100^0 C) \\ \\ Q_5 = (0.175 \ kg)(2090 \ J/kg.K)(19.5^0C)  \\ \\ Q_5 = 7132.125 \ J

The total heat required to change the steam into ice is:

Q = Q_1 + Q_2 + Q_3 + Q_4 +Q_5 \\ \\Q = (6788+393750+73255+58450+7132.125)J \\ \\ Q = 539325.125 \ J \\ \\ Q = 5.39*10^5 \ J

b)

The time taken to convert steam from 125 °C to 100°C is:

t_1 = \frac{Q_1}{P} = \frac{6738 \ J}{835 \ W}  = 8.12 \ s

The time taken to convert steam at  100°C to water at  100°C is:

t_2 = \frac{Q_2}{P} =\frac{393750}{834} =471.56 \ s

The time taken to convert water to 100° C to 0° C is:

t_3 = \frac{Q_3}{P} =\frac{73255}{834} = 87.73 \ s

The time taken to convert water at 0° to ice at 0° C is :

t_4 = \frac{Q_4}{P} =\frac{58450}{834} = 70.08  \ s

The time taken to convert ice from 0° C to -19.5° C is:

t_5 = \frac{Q_5}{P} =\frac{7132.125}{834} = 8.55  \ s

5 0
3 years ago
Cindy runs 500 meters every morning. It takes her 2 hours to complet
marta [7]

Answer:

250 / 2.5*10^2

Explanation:

7 0
2 years ago
A 20,000 kg truck is traveling at 10 m/s. Calculate the truck's momentum. (p = m v)
kow [346]

Answer:

200,000 and 20,000,000

Explanation:

Substituting the values into the equation of momentum, we get that the momentum is p = mv = 20,000*10 = 200,000. Using the equation provided to solve for the force the truck experienced, we find: 20,000*10/0.01 = 20,000,000.

I hope this helps!

8 0
3 years ago
A 800hz tuning fork is vibrating, producing a sound wave in the air.
blsea [12.9K]

Answer:

The frequency of the sound wave is 800Hz

The speed of sound in a is about 340m/s.

Velocity = frequency x wavelength

making wavelength the subject formula

wavelength = Velocity/frequency.

wavelength = 340/800

wavelength = 0.425m.

3 0
2 years ago
A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
Veronika [31]

Answer:

A) ω = 6v/19L

B) K2/K1 = 3/19

Explanation:

Mr = Mass of rod

Mb = Mass of bullet = Mr/4

Ir = (1/3)(Mr)L²

Ib = MbRb²

Radius of rotation of bullet Rb = L/2

A) From conservation of angular momentum,

L1 = L2

(Mb)v(L/2) = (Ir+ Ib)ω2

Where Ir is moment of inertia of rod while Ib is moment of inertia of bullet.

(Mr/4)(vL/2) = [(1/3)(Mr)L² + (Mr/4)(L/2)²]ω2

(MrvL/8) = [((Mr)L²/3) + (MrL²/16)]ω2

Divide each term by Mr;

vL/8 = (L²/3 + L²/16)ω2

vL/8 = (19L²/48)ω2

Divide both sides by L to obtain;

v/8 = (19L/48)ω2

Thus;

ω2 = 48v/(19x8L) = 6v/19L

B) K1 = K1b + K1r

K1 = (1/2)(Mb)v² + Ir(w1²)

= (1/2)(Mr/4)v² + (1/3)(Mr)L²(0²)

= (1/8)(Mr)v²

K2 = (1/2)(Isys)(ω2²)

I(sys) is (Ir+ Ib). This gives us;

Isys = (19L²Mr/48)

K2 =(1/2)(19L²Mr/48)(6v/19L)²

= (1/2)(36v²Mr/(48x19)) = 3v²Mr/152

Thus, the ratio, K2/K1 =

[3v²Mr/152] / (1/8)(Mr)v² = 24/152 = 3/19

3 0
3 years ago
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