Blank objects is a major cause of back injuries in the workplace

Can you find the magnetic field based on force? a straight segment of wire 35.0 cm long carrying a current of 1.40 a is in a uni

Lostsunrise [7]

The force exerted by a magnetic field on a wire carrying current is:
$F=ILB \sin \theta$
where I is the current, L the length of the wire, B the magnetic field intensity, and $\theta$ the angle between the wire and the direction of B.

In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is $53 ^{\circ}$ , so we can re-arrange the formula and substitute the numbers to find B:
$B= \frac{F}{IL \sin \theta}= \frac{0.20 N}{(1.40 A)(0.35 m)(\sin 53^{\circ})}=0.51 T$

3 0

3 years ago

A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart

Musya8 [376]

1) $0.61 m/s^2$

2) 13.9 s

Explanation:

1)

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

$g=\frac{GM}{r^2}$ (1)

where

G is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

$r=4R$

where

$R=6.37\cdot 10^6 m$ is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

$g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2$

2)

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

$g=0.61 m/s^2$ is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

$T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s$

4 0

3 years ago

A device used to measure a mass of an object is called

OLga [1]

Answer:

I am explain you in image

8 0

3 years ago

Convert to scientific notation:<br> 0.0035

Genrish500 [490]

3.5 x 10^-3 Should be it

3 0

3 years ago

Match each action with the object that is primarily responsible for causing that action.

Dafna11 [192]

Moon's Orbit <u>(C). Earth</u>
Tides on Earth <u>(B). Moon</u>
Earth's Orbit <u>(A). Sun</u>

<h3>Introduction</h3>

Hi ! I will help you to explain about gravity. Gravity is one part of the force that will pull two or more objects that interact with each other to the center of their weight. Because it is a force, and interacts with mass, the gravitational force can also cause an acceleration called gravitational acceleration.The characteristic of gravity are:

Mass cannot be affected by gravitational acceleration, because mass itself has formed gravitational interactions.
The weight of an object is something that can be affected by the acceleration of gravity, because weight is a derived quantity in Newtons (N)
The lighter object will fall to the heavier object because the center of mass will be closer to the object with greater mass.

<h2>Explanation</h2>

Let's go into more detail about my answer!

<h3>Moon's Orbit</h3>

The moon undergoes two motions, orbiting the Earth and orbiting the sun together. So, here the gravitational force from the Earth can be said to have more effect on the Moon. Without the influence of Earth's gravity, the moon will orbit the sun itself by the interaction of its own gravitational force with the sun.

<h3>Tides on Earth</h3>

The tides are caused by the Moon's gravitational force. Remember ! The Earth's gravitational force always points downwards to make a constant (so that water does not spill when it is hit by the Moon's gravity). The Moon's gravitational force also depends on how close it is to Earth.

<h3>Earth's Orbit</h3>

Like the Moon, the Earth orbits the sun. However, the sun is now creating a gravitational field. Not only for Earth, but for all objects in the solar system.

How long does it take the moon to go through an entire set of phases? brainly.com/question/26486572

8 0

2 years ago