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Anastaziya [24]
2 years ago
8

In a thunderstorm at 32.0°C, Reginald sees a bolt of lightning and hears the thunderclap 2.00s later. How far from Reginald did

the lightning strike? The speed of sound through air at 32.0° C is 350.2 m/s.
Physics
1 answer:
ratelena [41]2 years ago
5 0

Answer:

dont have the answer but you cute

Explanation:

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A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?
ipn [44]
Your answer would be A. You divide 96 by 16 to find the answer
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3 years ago
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15 points. give me the method.
AveGali [126]

Answer:

\boxed{{160 \:  m(s)}^{ - 1} }

Explanation:

if \:the \:  frequencies \: are \to \\   f_{1} =  640Hz  \\ and \\f_{2}   = 480Hz \:  \\ but \:  \boxed{v = f \gamma }:   f =  \frac{v}{ \gamma } \\ if \:  \gamma_{1}  -  \gamma _{2}  = 1 =  \gamma  \\ f_{1}  - f_{2}  = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 =  \boxed{{160 \:  m(s)}^{ - 1} }

5 0
2 years ago
Imagine a raindrop starting from rest in a cloud 2 km in the air. If it fell with no air friction at all, it would accelerate to
LenKa [72]

Answer:

2) 433 mph

Explanation:

The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:

v^2 = u^2 + 2ad

where

v is the final velocity

u = 0 is the initial velocity (the raindrop starts from rest)

a = g = 9.8 m/s^2 is the acceleration due to gravity

d = 2 km = 2000 m is the distance covered

Solving for v,

v=\sqrt{u^2 +2gd}=\sqrt{0^2+2(9.8 m/s^2)(2000)}=198 m/s

And keeping in mind that

1 mile = 1609 metres

1 hour = 3600 s

The speed converted into miles per hour is

v=198 \frac{m}{s}\cdot \frac{3600 s/h}{1609 m/mi}=433 mph

5 0
3 years ago
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Answer: I think it would be 72 because 12x3=36 and then all the chick have 2 feet each so you would multiply t but 2 and that would be 72

Explanation:

5 0
2 years ago
Okay okay two questions heh
tensa zangetsu [6.8K]
The answer for question 2 i guess it’s c
3 0
2 years ago
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