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Anastaziya [24]
2 years ago
8

In a thunderstorm at 32.0°C, Reginald sees a bolt of lightning and hears the thunderclap 2.00s later. How far from Reginald did

the lightning strike? The speed of sound through air at 32.0° C is 350.2 m/s.
Physics
1 answer:
ratelena [41]2 years ago
5 0

Answer:

dont have the answer but you cute

Explanation:

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6. Which of the following statements is true for displacement ?
Lostsunrise [7]

Both are false..........

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(A) Electricity and Magnetism
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electricity

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When is the next total solar eclipse in illinois
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April 8, 2024

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7 0
3 years ago
A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstr
Ksju [112]

Answer:

Explanation:

Given that

g=9.8m/s²

The spring constant is

k=50N/m

The length of the bungee cord is

Lo=32m

Height of bridge which one end of the bungee is tied is 91m

A steel ball of mass 92kg is attached to the other end of the bungee.

The potential energy(Us) of the steel ball before dropped from the bridge is given as

P.E= mgh

P.E= 92×9.8×91

P.E= 82045.6 J

Us= 82045.6 J

Potential energy)(Uc) of the cord is given as

Uc= ½ke²

Where 'e' is the extension

Then the extension is final height extended by cord minus height of cord

e=hf - hi

e=hf - 32

Uc= ½×50×(hf-32)²

Uc=25(hf-32)²

Using conservation of energy,

Then,

The potential energy of free fall equals the potential energy in string

Uc=Us

25(hf-32)²=82045.6

(hf-32)² = 82045.6/25

(hf-32)²=3281.825

Take square root of both sides

√(hf-32)²=√(3281.825)

hf-32=57.29

hf=57.29+32

hf=89.29m

We neglect the negative sign of the root because the string cannot compressed

3 0
3 years ago
If an object moving at 12 m/s has a kinetic energy of 72 j what is the mass
EleoNora [17]
Simply, apply the formula E = \frac{1}{2}mv^{2} and insert the values of m = mass, v = velocity and E = Energy.
The result will be 72J =  \frac{1}{2}m(12m/s)^{2}, m = 1 kg
5 0
3 years ago
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