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Sergeeva-Olga [200]
3 years ago
13

Sulfur dioxide (SO2) is an unwelcome result

Chemistry
1 answer:
REY [17]3 years ago
4 0

Answer: 5782

Explanation:

5782

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3. In the apparatus below, the seawater is an example of a(n) ——
san4es73 [151]

In the apparatus of the electrochemical cell, the seawater is an example of an electrolyte.

<h3>What is an electrolyte?</h3>

An electrolyte is a component of the electrochemical cell that is a solution of solvent or water that contains dissolved ions.

The salts of sodium, chloride, and potassium are the main components of seawater and a great electrolyte.

Therefore seawater is an example of an electrolyte.

Learn more about electrolytes here:

brainly.com/question/2285692

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3 0
2 years ago
O2 + C3H2 + H2O + CO2<br> Reaction type?
Kobotan [32]

Answer:

Combustion is the reaction type if you meant to put a "=" in between C3H2 and H2O

3 0
4 years ago
Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
Elis [28]
Hello :))

Your question was:Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
The answer is: Sublimation

Hope this helps!
Good day! :D
3 0
3 years ago
What is the boiling point of a sample of Propanone at 180kpa?
shepuryov [24]

Answer: The boiling point of a sample of Propanone at 180 kPa is 75 C. The correct answer is 2.

Explanation:

Propanone is more commonly known under the name "acetone." The boiling point of this compound at 180 kPa will be 75 C. It is an organic compound and its formula is (CH3)2CO.

This compound does not any color, it is highly flammable, and volatile. This compound does have a distinguished odor. It is used in labs, in industry settings, and in the home for various things. The human body does produce this compound naturally and the body disposes of this compound.

3 0
3 years ago
Having difficulty understanding formulas involved. Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O.
Luda [366]
To determine the quantity of pure CaCl2 from the given amount of CaCl2.9H2O, we use the ratio of CaCl2 to CaCl2.9H2O. From the formula the ratio would 1 is to 1 We calculate as follows:

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( <span>110.98 g / 1 mol ) = 3.05 g CaCl2

Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
7 0
3 years ago
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