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4 years ago

A 1.5 long string vibrates in 4 segments. If the speed of the wave is 300/sec . What would be wave length of the string?

Physics

1 answer:

blondinia [14]4 years ago

6 0

The wavelength is 0.75 m

Explanation:

A standing wave is created on a string when a vibration is imparted on the string, and the string is fixed at the two ends (so that the two ends correspond to two nodes, where the oscillation is zero).

If there are no other nodes in the string, then the string is said to be vibrating at its fundamental frequency. For a string vibrating at its fundamental frequency, the wavelength of the standing wave is equal to twice the length of the string:

$\lambda_1 = 2L$

where L is the length of the string.

The fundamental frequency is therefore given by

$f_1=\frac{v}{\lambda_1}=\frac{v}{2L}$

where v is the speed of the wave.

However, in this case the string is vibrating in 4 segments: this means that the string is vibrating at its 4th harmonic (4th mode of vibration). The frequency of the 4th harmonic is given by

$f_4 = 4 f_1 = 4(\frac{v}{2L}) = \frac{2v}{L}$

And correspondigly, the wavelength of the 4th harmonic is

$\lambda_4 = \frac{v}{f}=\frac{v}{2v/L}=\frac{L}{2}$

This string has a length of

L = 1.5 m

Therefore, the wavelength when it vibrates in 4 segments is:

$\lambda_4 = \frac{1.5}{2}=0.75 m$

Learn more about waves:

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The answer is to the ground.

Gravity refers to the force that holds together the universe. On Earth, the gravity attempts to change the velocity of all the objects on the Earth's surface toward the ground at a rate of 9.8 meters per second squared according to Galileo.

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3 years ago

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B. The "Learner" was working with Milgram.

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3 years ago

On a hot day, the temperature of a 65,000-L swimming pool increases by 1.20°C. What is the net heat transfer during this heating

vichka [17]

Answer:

326149.2 KJ

Explanation:

The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:

Q = m*cv*ΔT

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The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.

We replace the data and get:

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3 years ago

A nonuniform, but spherically symmetric, distribution of charge has a charge density ρ(r) given as follows: ρ(r)=ρ0(1−r/r) for r

Nadusha1986 [10]

A)<span>
dQ = ρ(r) * A * dr = ρ0(1 - r/R) (4πr²)dr = 4π * ρ0(r² - r³/R) dr
which when integrated from 0 to r is
total charge = 4π * ρ0 (r³/3 + r^4/(4R))
and when r = R our total charge is
total charge = 4π*ρ0(R³/3 + R³/4) = 4π*ρ0*R³/12 = π*ρ0*R³ / 3
and after substituting ρ0 = 3Q / πR³ we have
total charge = Q ◄

B) E = kQ/d²
since the distribution is symmetric spherically

C) dE = k*dq/r² = k*4π*ρ0(r² - r³/R)dr / r² = k*4π*ρ0(1 - r/R)dr
so
E(r) = k*4π*ρ0*(r - r²/(2R)) from zero to r is
and after substituting for ρ0 is
E(r) = k*4π*3Q(r - r²/(2R)) / πR³ = 12kQ(r/R³ - r²/(2R^4))
which could be expressed other ways.

D) dE/dr = 0 = 12kQ(1/R³ - r/R^4) means that
r = R for a min/max (and we know it's a max since r = 0 is a min).

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3 years ago

Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of t

dsp73

Answer:

With the help of formula.

Explanation:

We can calculate the electric potential of any point through the formula of electric potential which is given below.

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Symbolically it can be written as, V = k q/ r where

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If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.

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