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2 years ago

Select all of the statements that are true.

2 answers:

5 0

1 is true,
2 is definitely false 
3 is also completely false because 
4 is true. 

So 1&4

sveta [45]2 years ago

3 0

According to the atomic model given by Rutherford, the atom is a dense, and tiny positively charged core known as the nucleus, which is enveloped by lighter and negatively charged electrons. An electron refers to a stable subatomic particle comprising a negative charge, which is found in all the atoms.

The following are the correct statements:

1. The electrons are situated in orbits or shells around the atom.

2. The electrons are traveling so fast, that it becomes almost impossible to locate their precise locations.

You might be interested in

How many moles are equal to 2.188E+23 atoms of iron?

rusak2 [61]

2.188*10^23 atoms of iron
6.022*10^23 atoms/mole
(2.188*10^23 atoms of iron)/(6.022*10^23 atoms/mol)~.3633 moles of iron

Hope this helps!

7 0

2 years ago

How many atoms are in 3 moI of helium

disa [49]

Mark Brainiest please

Answer:
1.8 x 10^24

One mole of helium has 6.02 x 10^23 atoms, thise number is also called Avogadro's number or constant.
If we need number of atoms for 3 moles so simply, multiply 3 by 6.02 x 10^23
so,
Number of atoms for 3 moles = 3 x ()
Number of atoms will be = 1.806x10^24

5 0

2 years ago

Read 2 more answers

Ok me and my brother had an argument and threw a frok at me Saying he didnt

max2010maxim [7]

LOL

RIP you

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

frog you mean? or? huh

4 0

2 years ago

Please help me solve this!

yulyashka [42]

Answer : The image is attached below.

Explanation :

For $O_3$ :

Molar mass, M = 48 g/mol

Mass, m = 24 g

Moles, n = $\frac{m}{M}=\frac{24g}{48g/mol}=0.5mol$

Number of particles, N = $n\times 6.022\times 10^{23}=0.5\times 6.022\times 10^{23}=3.0\times 10^{23}$

For $NH_3$ :

Molar mass, M = 17 g/mol

Mass, m = 170 g

Moles, n = $\frac{m}{M}=\frac{170g}{17g/mol}=10mol$

Number of particles, N = $n\times 6.022\times 10^{23}=10\times 6.022\times 10^{23}=6.0\times 10^{24}$

For $F_2$ :

Molar mass, M = 38 g/mol

Mass, m = 38 g

Moles, n = $\frac{m}{M}=\frac{38g}{38g/mol}=1mol$

Number of particles, N = $n\times 6.022\times 10^{23}=1\times 6.022\times 10^{23}=6.0\times 10^{23}$

For $CO_2$ :

Molar mass, M = 44 g/mol

Moles, n = 0.10 mol

Mass, m = $n\times M=0.10mol\times 44g/mol=4.4g$

Number of particles, N = $n\times 6.022\times 10^{23}=0.10\times 6.022\times 10^{23}=6.0\times 10^{22}$

For $NO_2$ :

Molar mass, M = 46 g/mol

Moles, n = 0.20 mol

Mass, m = $n\times M=0.20mol\times 46g/mol=9.2g$

Number of particles, N = $n\times 6.022\times 10^{23}=0.20\times 6.022\times 10^{23}=1.2\times 10^{23}$

For $Ne$ :

Molar mass, M = 20 g/mol

Number of particles = $1.5\times 10^{23}$

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{1.5\times 10^{23}}{6.022\times 10^{23}}=0.25mol$

Mass, m = $n\times M=0.25mol\times 20g/mol=5g$

For $N_2O$ :

Molar mass, M = 44 g/mol

Number of particles = $1.2\times 10^{24}$

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{1.2\times 10^{24}}{6.022\times 10^{23}}=1.9mol$

Mass, m = $n\times M=1.9mol\times 44g/mol=83.6g$

For unknown substance:

Number of particles = $3.0\times 10^{23}$

Mass, m = 8.5 g

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{3.0\times 10^{23}}{6.022\times 10^{23}}=0.50mol$

Molar mass, M = $\frac{m}{n}=\frac{8.5g}{0.50mol}=17g/mol$

The substance is $NH_3$ .

3 0

2 years ago

I really appreciate I need help

Leno4ka [110]

The bridge is completely surrounded by cold air in the winter and by hot air in the summer. It is not insulated by the ground beneath it

3 0

2 years ago

Read 2 more answers