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nadezda [96]
4 years ago
14

Noble Gases (18): (Name all noble gases)

Chemistry
1 answer:
Paul [167]4 years ago
3 0

Answer :

  • The Noble gasses are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn).
  • When air is cold, Oxygen liquefies first at -182^oC. N_2 liquefies at -195^oC. About 1% of the air is still gas composed of the noble gas Argon, Ar.
  • One noble gas was discovered on the sun. It’s spectrum was identify first. This is Helium, He.
  • One of noble gas is radioactive and seeps up your basement floors and walls. It is Radon, Rn.
  • This noble gas is used in electronic flashes and other bright lights. It is Xenon, Xe.
  • This noble gas is best known for its orange color in gas discharge tubes. It is used for signs that bear its name. It is Neon, Ne.
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14.4g

Explanation:

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Determine the empirical formula of a compound containing 40. 6 grams of carbon, 5. 1 grams of hydrogen, and 54. 2 grams of oxyge
zavuch27 [327]

The empirical formula is C₂H₃O₂

<h3>What is Empirical formula of a compound ?</h3>

The empirical formula is the simplest whole number ratio of elements present in a compound.

The total molar mass of the compound is 118.084 g/mol.

mass of Carbon present = 40.6

mass of Hydrogen present = 5.1 grams

mass of Oxygen present = 2 grams

Moles of C = 40.6/12 = 3.38

Moles of H = 5.1/1.008 = 5

Moles of Oxygen = 54.2/15.999 = 3.38

Ratio of Moles of C to Oxygen is 1 : 1

Ratio of Moles of C to H is 1/1.5

Multiplying each mole fraction by 2

The empirical formula is C₂H₃O₂

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5 0
2 years ago
How many moles of O₂ would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 60.6% yi
saw5 [17]

Answer:

116 is the right answer of these

3 0
3 years ago
Read 2 more answers
Calculate the massa of water produced if 1.00 gran of hydrogen is burned in 10.00 grams of oxygen
Anna71 [15]
The first step to this question is finding the balanced chemical reaction.
H₂+1/2O₂⇒H₂O
Then you need to find the limiting reagent by finding the moles of each reactant then finding how much product each amount of reactants will form.  The reactant that produces the least amount of product is the limiting reagent.
moles of H₂:
1g/(1g/mol)=1mol
moles of O₂:
10g/32g/mol=0.3125mol
moles of H₂O formed with amount of H₂:
1molH₂x(1molH₂O/1molH₂O)=1molH₂O
moles of H₂O formed with amount of O₂:
0.3125molO₂x(1molH₂O/0.5molO₂)=0.625molH₂O
Since less water is produced with the amount of oxygen given, oxygen is the limiting reagent and the moles of water formed from the oxygen is the moles of H₂O we will use to find the amount of H₂O produced.
0.625molH₂Ox18g/mol=11.25g H₂O
3 0
3 years ago
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