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nadezda [96]
4 years ago
14

Noble Gases (18): (Name all noble gases)

Chemistry
1 answer:
Paul [167]4 years ago
3 0

Answer :

  • The Noble gasses are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn).
  • When air is cold, Oxygen liquefies first at -182^oC. N_2 liquefies at -195^oC. About 1% of the air is still gas composed of the noble gas Argon, Ar.
  • One noble gas was discovered on the sun. It’s spectrum was identify first. This is Helium, He.
  • One of noble gas is radioactive and seeps up your basement floors and walls. It is Radon, Rn.
  • This noble gas is used in electronic flashes and other bright lights. It is Xenon, Xe.
  • This noble gas is best known for its orange color in gas discharge tubes. It is used for signs that bear its name. It is Neon, Ne.
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C. AlCl3 is a covalent compound.

Explanation:

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The mass of a neutron is 1.67 x 10^-24 g. Approximately what number of neutrons would equal a mass of one gram?
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1. a sulfur-32 atom contains 16 protons, 16 neutrons, and 16 electrons. what is the mass (in grams) of a sulfur-32 atom?

The mass in grams of a sulfur-32 atom is 32.

That is how the isotopes are identified, showing the mass number of the isotope, which is the sum of protons and neutrons: 16 protons + 16 neutrons = 32 mass number = mass in grams of the isotope.

2. the mass of a neutron is 1.67 x 10-24 g. approximately what number of neutrons would equal a mass of one gram?

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The pH scale measures the relative strength of acids or bases in ___________. a Isolation b Metals c Solutions d Hydrocarbons
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Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con
anyanavicka [17]

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 }  *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O}  *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

5 0
3 years ago
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