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Rudiy27
3 years ago
15

How do you calculate acceleration on a velocity time graph

Physics
2 answers:
adell [148]3 years ago
7 0
Acceleration on a velocity time graph is found by calculating the change in the velocity over the change in time, or in other words, the slope. To do so, it's (final v-initial v)/(final t-initial t), where v is the velocity and t is time. Just find the final point you are looking for on the velocity time graph and determine its velocity and time. Then do the same for the initial point on the velocity time graph. Subtract the final velocity from the initial velocity and divide it by the final time minus the initial time and you will find the velocity for that interval. If you are looking for the instantaneous velocity at one specific point and not a interval, it's just the slope of the line at that point in time.
n200080 [17]3 years ago
5 0

Answer:

\large \boxed{\mathrm{slope \ of \ the \ graph}}

Explanation:

\displaystyle acceleration = \frac{change \ in \ velocity }{elapsed \ time}

\displaystyle acceleration = \frac{\Delta V }{\Delta t}

The average acceleration over a certain time interval tells us by how much the velocity changes per time unit over that interval.

The slope or rise over run of a velocity-time graph tells us about the average acceleration.

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4 0
3 years ago
Read 2 more answers
A ball is dropped from an aircraft flying at an altitude of 8,848 meters assuming gravity is 9.8m/s what is the total amount of
Dafna11 [192]
In this question, you're determining the time (t) taken for an object to fall from a distance (d).

The equation to represent this is:
Time equals the square root of 2 times the distance divided by the gravitational force of earth.
In equation from it looks like this (there isn't an icon to represent square root so just pretend like there's a square root there):
t = 2d/g (square-rooted)

d = 8,848m and g = 9.8m/s

Now plug in the information we have:
t = 2 x 8,848m/9.8m/s (square-rooted)

The first step is to multiply 2 times 8,848m:
t = 17,696m/9.8m/s (square-rooted)

Now divide 9.8m/s by 17,696m (note that the two m's (meters) cancels out leaving you with only s (seconds):
t = 1805.72s (square-rooted)

Now for the last step, find the square root of the remaining number:
t = 42.5s

So the time it takes the ball to drop from the height (distance) of 8,848 meters, and falling with the gravitational pull of 9.8 meters per second is 42.5 seconds.

I hope this helps :)

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3 years ago
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Lapatulllka [165]
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Answer:

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That means that magnetic field due to the surrounding magnets is always in the same direction, but the magnetic field due to the rotating   loop of wire is continually changing so that it will always oppose the surrounding field which remains in a constant direction.

This is most easily seen in a "DC - direct current motor".

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Answer:

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