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Rudiy27
4 years ago
15

How do you calculate acceleration on a velocity time graph

Physics
2 answers:
adell [148]4 years ago
7 0
Acceleration on a velocity time graph is found by calculating the change in the velocity over the change in time, or in other words, the slope. To do so, it's (final v-initial v)/(final t-initial t), where v is the velocity and t is time. Just find the final point you are looking for on the velocity time graph and determine its velocity and time. Then do the same for the initial point on the velocity time graph. Subtract the final velocity from the initial velocity and divide it by the final time minus the initial time and you will find the velocity for that interval. If you are looking for the instantaneous velocity at one specific point and not a interval, it's just the slope of the line at that point in time.
n200080 [17]4 years ago
5 0

Answer:

\large \boxed{\mathrm{slope \ of \ the \ graph}}

Explanation:

\displaystyle acceleration = \frac{change \ in \ velocity }{elapsed \ time}

\displaystyle acceleration = \frac{\Delta V }{\Delta t}

The average acceleration over a certain time interval tells us by how much the velocity changes per time unit over that interval.

The slope or rise over run of a velocity-time graph tells us about the average acceleration.

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A car goes from 0 to 100 km/hr in 10 seconds. What is its acceleration
makvit [3.9K]

Answer:

a= 2.7 m/s^2

Explanation:

acceleration: a

speed: V

Vf = final speed

Vi= initial speed (initial = beginning)

100 km/hour --> m/s

divide the speed value by 3.6

100/3.6= 27.8 m/s

a = \frac{final speed - initialspeed}{time}

a= \frac{Vf - Vi}{t} \\

a= \frac{27-0}{10}

a= \frac{27}{10}

a= 2.7 m/s^2

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3 years ago
What is the difference between an electrolyte and a nonelectrolyte
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Answer:

The difference between the Electrolyte and Non-Electrolyte are given in the explanation part.    

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4 years ago
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I need to solve this problem ​
castortr0y [4]

Answer:

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V = f λ      and V (speed) proportional λ    for a fixed frequency

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F2 / F1 = (λ2 / λ1)^2    other items are constant

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The tension must be increased to 9 / 4 of  the original tension

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F2 / F1 = (V2 / V1)^2

Since V = f λ      Velocity is proportional to λ  for a fixed frequency

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