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3 years ago

A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.

Physics

1 answer:

Ugo [173]3 years ago

5 0

Answer:

(A) 10052.2 m/s²

(B) 0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds

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Answer:

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solution

we get here induced EMF of induction is express as

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3 years ago

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3 years ago

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Answer:

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$l= l' \sqrt{1-\frac{v^2}{c^2}}$

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3 years ago