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Savatey [412]
3 years ago
9

What are the three places where ribisomes occur in a cell​

Physics
1 answer:
irina [24]3 years ago
4 0

Answer: Rough endoplasmic reticulum, cytoplasm, inside mitochondria

Explanation:

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A child is sliding down a slide at the playgound. is mechanicalenergy conserved
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No. Mechanical energy is not conserved.  There's quite a bit of friction on the slide.  So some of the potential energy is lost to heat on the way down, and the child arrives at the bottom with hot pants and less kinetic energy than you might expect.

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Please help me i dont understand it <br><br><br><br> This subject is Earth science
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6 0
3 years ago
Examine the spectra of the four unknown substances shown below. What can you conclude?
NARA [144]
Line spectra are obtained when individual elements are heated using a high-voltage electrical discharge. This heating causes excitation of the element and a subsequent emission of distinct lines of colored light are obtained. Each element has its own unique emission line spectrum; therefore, if any of the tested substances were the same, their spectra would match. However, this is not the case so none of the substances are the same.
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3 years ago
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When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rat
svlad2 [7]

Answer:

343/1500

Explanation:

Power: This can be defined as the product force and velocity. The S.I unit of power is Watt (w).

From the question,

P' = mg×v................. Equation 1

Where P' = power used to gain an altitude, m = mass of the engine, g = acceleration due to gravity of the engine, v = velocity of the engine.

Given: m = 700 kg, v = 2.5 m/s, g = 9.8 m/s²

Substitute into equation 1

P' = 700(2.5)(9.8)

P' = 17150 W.

If the full power generated by the engine = 75000 W

The fraction of the engine power used to make the climb = 17150/75000

= 343/1500

8 0
3 years ago
In 0.601 s, a 13.1-kg block is pulled through a distance of 4.19 m on a frictionless horizontal surface, starting from rest. The
Naya [18.7K]

Answer:

0.615 m

Explanation:

We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.

The acceleration is determined using the equation of motion.

Given parameters:

Initial velocity, <em>u</em> = 0.00 m/s

Distance, <em>s</em> = 4.19 m

Time, <em>t</em> = 0.601 s

We use the equation

s = ut+\frac{1}{2}at^2

With <em>u</em> = 0.00 m/s,

s = \frac{1}{2}at^2

a = \dfrac{2s}{t^2}

a = \dfrac{2\times4.19\text{ m}}{(0.601\text{ s})^2} = 23.2\text{ m/s}^2

The force is

F = (13.1\text{ kg})(23.2\text{ m/s}^2) = 303.92 \text{ N}

From Hooke's law, the extension, <em>e</em>, of a string is given by

e = \dfrac{F}{k}

where <em>k</em> is the spring constant.

Hence,

e = \dfrac{303.92\text{ N}}{494\text{ N/m}} = 0.615\text{ m}

4 0
3 years ago
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